Based on kernel version 4.3. Page generated on 2015-11-02 12:50 EST.
1 ============================ 2 LINUX KERNEL MEMORY BARRIERS 3 ============================ 4 5 By: David Howells <dhowells@redhat.com> 6 Paul E. McKenney <paulmck@linux.vnet.ibm.com> 7 8 Contents: 9 10 (*) Abstract memory access model. 11 12 - Device operations. 13 - Guarantees. 14 15 (*) What are memory barriers? 16 17 - Varieties of memory barrier. 18 - What may not be assumed about memory barriers? 19 - Data dependency barriers. 20 - Control dependencies. 21 - SMP barrier pairing. 22 - Examples of memory barrier sequences. 23 - Read memory barriers vs load speculation. 24 - Transitivity 25 26 (*) Explicit kernel barriers. 27 28 - Compiler barrier. 29 - CPU memory barriers. 30 - MMIO write barrier. 31 32 (*) Implicit kernel memory barriers. 33 34 - Locking functions. 35 - Interrupt disabling functions. 36 - Sleep and wake-up functions. 37 - Miscellaneous functions. 38 39 (*) Inter-CPU locking barrier effects. 40 41 - Locks vs memory accesses. 42 - Locks vs I/O accesses. 43 44 (*) Where are memory barriers needed? 45 46 - Interprocessor interaction. 47 - Atomic operations. 48 - Accessing devices. 49 - Interrupts. 50 51 (*) Kernel I/O barrier effects. 52 53 (*) Assumed minimum execution ordering model. 54 55 (*) The effects of the cpu cache. 56 57 - Cache coherency. 58 - Cache coherency vs DMA. 59 - Cache coherency vs MMIO. 60 61 (*) The things CPUs get up to. 62 63 - And then there's the Alpha. 64 65 (*) Example uses. 66 67 - Circular buffers. 68 69 (*) References. 70 71 72 ============================ 73 ABSTRACT MEMORY ACCESS MODEL 74 ============================ 75 76 Consider the following abstract model of the system: 77 78 : : 79 : : 80 : : 81 +-------+ : +--------+ : +-------+ 82 | | : | | : | | 83 | | : | | : | | 84 | CPU 1 |<----->| Memory |<----->| CPU 2 | 85 | | : | | : | | 86 | | : | | : | | 87 +-------+ : +--------+ : +-------+ 88 ^ : ^ : ^ 89 | : | : | 90 | : | : | 91 | : v : | 92 | : +--------+ : | 93 | : | | : | 94 | : | | : | 95 +---------->| Device |<----------+ 96 : | | : 97 : | | : 98 : +--------+ : 99 : : 100 101 Each CPU executes a program that generates memory access operations. In the 102 abstract CPU, memory operation ordering is very relaxed, and a CPU may actually 103 perform the memory operations in any order it likes, provided program causality 104 appears to be maintained. Similarly, the compiler may also arrange the 105 instructions it emits in any order it likes, provided it doesn't affect the 106 apparent operation of the program. 107 108 So in the above diagram, the effects of the memory operations performed by a 109 CPU are perceived by the rest of the system as the operations cross the 110 interface between the CPU and rest of the system (the dotted lines). 111 112 113 For example, consider the following sequence of events: 114 115 CPU 1 CPU 2 116 =============== =============== 117 { A == 1; B == 2 } 118 A = 3; x = B; 119 B = 4; y = A; 120 121 The set of accesses as seen by the memory system in the middle can be arranged 122 in 24 different combinations: 123 124 STORE A=3, STORE B=4, y=LOAD A->3, x=LOAD B->4 125 STORE A=3, STORE B=4, x=LOAD B->4, y=LOAD A->3 126 STORE A=3, y=LOAD A->3, STORE B=4, x=LOAD B->4 127 STORE A=3, y=LOAD A->3, x=LOAD B->2, STORE B=4 128 STORE A=3, x=LOAD B->2, STORE B=4, y=LOAD A->3 129 STORE A=3, x=LOAD B->2, y=LOAD A->3, STORE B=4 130 STORE B=4, STORE A=3, y=LOAD A->3, x=LOAD B->4 131 STORE B=4, ... 132 ... 133 134 and can thus result in four different combinations of values: 135 136 x == 2, y == 1 137 x == 2, y == 3 138 x == 4, y == 1 139 x == 4, y == 3 140 141 142 Furthermore, the stores committed by a CPU to the memory system may not be 143 perceived by the loads made by another CPU in the same order as the stores were 144 committed. 145 146 147 As a further example, consider this sequence of events: 148 149 CPU 1 CPU 2 150 =============== =============== 151 { A == 1, B == 2, C = 3, P == &A, Q == &C } 152 B = 4; Q = P; 153 P = &B D = *Q; 154 155 There is an obvious data dependency here, as the value loaded into D depends on 156 the address retrieved from P by CPU 2. At the end of the sequence, any of the 157 following results are possible: 158 159 (Q == &A) and (D == 1) 160 (Q == &B) and (D == 2) 161 (Q == &B) and (D == 4) 162 163 Note that CPU 2 will never try and load C into D because the CPU will load P 164 into Q before issuing the load of *Q. 165 166 167 DEVICE OPERATIONS 168 ----------------- 169 170 Some devices present their control interfaces as collections of memory 171 locations, but the order in which the control registers are accessed is very 172 important. For instance, imagine an ethernet card with a set of internal 173 registers that are accessed through an address port register (A) and a data 174 port register (D). To read internal register 5, the following code might then 175 be used: 176 177 *A = 5; 178 x = *D; 179 180 but this might show up as either of the following two sequences: 181 182 STORE *A = 5, x = LOAD *D 183 x = LOAD *D, STORE *A = 5 184 185 the second of which will almost certainly result in a malfunction, since it set 186 the address _after_ attempting to read the register. 187 188 189 GUARANTEES 190 ---------- 191 192 There are some minimal guarantees that may be expected of a CPU: 193 194 (*) On any given CPU, dependent memory accesses will be issued in order, with 195 respect to itself. This means that for: 196 197 WRITE_ONCE(Q, P); smp_read_barrier_depends(); D = READ_ONCE(*Q); 198 199 the CPU will issue the following memory operations: 200 201 Q = LOAD P, D = LOAD *Q 202 203 and always in that order. On most systems, smp_read_barrier_depends() 204 does nothing, but it is required for DEC Alpha. The READ_ONCE() 205 and WRITE_ONCE() are required to prevent compiler mischief. Please 206 note that you should normally use something like rcu_dereference() 207 instead of open-coding smp_read_barrier_depends(). 208 209 (*) Overlapping loads and stores within a particular CPU will appear to be 210 ordered within that CPU. This means that for: 211 212 a = READ_ONCE(*X); WRITE_ONCE(*X, b); 213 214 the CPU will only issue the following sequence of memory operations: 215 216 a = LOAD *X, STORE *X = b 217 218 And for: 219 220 WRITE_ONCE(*X, c); d = READ_ONCE(*X); 221 222 the CPU will only issue: 223 224 STORE *X = c, d = LOAD *X 225 226 (Loads and stores overlap if they are targeted at overlapping pieces of 227 memory). 228 229 And there are a number of things that _must_ or _must_not_ be assumed: 230 231 (*) It _must_not_ be assumed that the compiler will do what you want 232 with memory references that are not protected by READ_ONCE() and 233 WRITE_ONCE(). Without them, the compiler is within its rights to 234 do all sorts of "creative" transformations, which are covered in 235 the Compiler Barrier section. 236 237 (*) It _must_not_ be assumed that independent loads and stores will be issued 238 in the order given. This means that for: 239 240 X = *A; Y = *B; *D = Z; 241 242 we may get any of the following sequences: 243 244 X = LOAD *A, Y = LOAD *B, STORE *D = Z 245 X = LOAD *A, STORE *D = Z, Y = LOAD *B 246 Y = LOAD *B, X = LOAD *A, STORE *D = Z 247 Y = LOAD *B, STORE *D = Z, X = LOAD *A 248 STORE *D = Z, X = LOAD *A, Y = LOAD *B 249 STORE *D = Z, Y = LOAD *B, X = LOAD *A 250 251 (*) It _must_ be assumed that overlapping memory accesses may be merged or 252 discarded. This means that for: 253 254 X = *A; Y = *(A + 4); 255 256 we may get any one of the following sequences: 257 258 X = LOAD *A; Y = LOAD *(A + 4); 259 Y = LOAD *(A + 4); X = LOAD *A; 260 {X, Y} = LOAD {*A, *(A + 4) }; 261 262 And for: 263 264 *A = X; *(A + 4) = Y; 265 266 we may get any of: 267 268 STORE *A = X; STORE *(A + 4) = Y; 269 STORE *(A + 4) = Y; STORE *A = X; 270 STORE {*A, *(A + 4) } = {X, Y}; 271 272 And there are anti-guarantees: 273 274 (*) These guarantees do not apply to bitfields, because compilers often 275 generate code to modify these using non-atomic read-modify-write 276 sequences. Do not attempt to use bitfields to synchronize parallel 277 algorithms. 278 279 (*) Even in cases where bitfields are protected by locks, all fields 280 in a given bitfield must be protected by one lock. If two fields 281 in a given bitfield are protected by different locks, the compiler's 282 non-atomic read-modify-write sequences can cause an update to one 283 field to corrupt the value of an adjacent field. 284 285 (*) These guarantees apply only to properly aligned and sized scalar 286 variables. "Properly sized" currently means variables that are 287 the same size as "char", "short", "int" and "long". "Properly 288 aligned" means the natural alignment, thus no constraints for 289 "char", two-byte alignment for "short", four-byte alignment for 290 "int", and either four-byte or eight-byte alignment for "long", 291 on 32-bit and 64-bit systems, respectively. Note that these 292 guarantees were introduced into the C11 standard, so beware when 293 using older pre-C11 compilers (for example, gcc 4.6). The portion 294 of the standard containing this guarantee is Section 3.14, which 295 defines "memory location" as follows: 296 297 memory location 298 either an object of scalar type, or a maximal sequence 299 of adjacent bit-fields all having nonzero width 300 301 NOTE 1: Two threads of execution can update and access 302 separate memory locations without interfering with 303 each other. 304 305 NOTE 2: A bit-field and an adjacent non-bit-field member 306 are in separate memory locations. The same applies 307 to two bit-fields, if one is declared inside a nested 308 structure declaration and the other is not, or if the two 309 are separated by a zero-length bit-field declaration, 310 or if they are separated by a non-bit-field member 311 declaration. It is not safe to concurrently update two 312 bit-fields in the same structure if all members declared 313 between them are also bit-fields, no matter what the 314 sizes of those intervening bit-fields happen to be. 315 316 317 ========================= 318 WHAT ARE MEMORY BARRIERS? 319 ========================= 320 321 As can be seen above, independent memory operations are effectively performed 322 in random order, but this can be a problem for CPU-CPU interaction and for I/O. 323 What is required is some way of intervening to instruct the compiler and the 324 CPU to restrict the order. 325 326 Memory barriers are such interventions. They impose a perceived partial 327 ordering over the memory operations on either side of the barrier. 328 329 Such enforcement is important because the CPUs and other devices in a system 330 can use a variety of tricks to improve performance, including reordering, 331 deferral and combination of memory operations; speculative loads; speculative 332 branch prediction and various types of caching. Memory barriers are used to 333 override or suppress these tricks, allowing the code to sanely control the 334 interaction of multiple CPUs and/or devices. 335 336 337 VARIETIES OF MEMORY BARRIER 338 --------------------------- 339 340 Memory barriers come in four basic varieties: 341 342 (1) Write (or store) memory barriers. 343 344 A write memory barrier gives a guarantee that all the STORE operations 345 specified before the barrier will appear to happen before all the STORE 346 operations specified after the barrier with respect to the other 347 components of the system. 348 349 A write barrier is a partial ordering on stores only; it is not required 350 to have any effect on loads. 351 352 A CPU can be viewed as committing a sequence of store operations to the 353 memory system as time progresses. All stores before a write barrier will 354 occur in the sequence _before_ all the stores after the write barrier. 355 356 [!] Note that write barriers should normally be paired with read or data 357 dependency barriers; see the "SMP barrier pairing" subsection. 358 359 360 (2) Data dependency barriers. 361 362 A data dependency barrier is a weaker form of read barrier. In the case 363 where two loads are performed such that the second depends on the result 364 of the first (eg: the first load retrieves the address to which the second 365 load will be directed), a data dependency barrier would be required to 366 make sure that the target of the second load is updated before the address 367 obtained by the first load is accessed. 368 369 A data dependency barrier is a partial ordering on interdependent loads 370 only; it is not required to have any effect on stores, independent loads 371 or overlapping loads. 372 373 As mentioned in (1), the other CPUs in the system can be viewed as 374 committing sequences of stores to the memory system that the CPU being 375 considered can then perceive. A data dependency barrier issued by the CPU 376 under consideration guarantees that for any load preceding it, if that 377 load touches one of a sequence of stores from another CPU, then by the 378 time the barrier completes, the effects of all the stores prior to that 379 touched by the load will be perceptible to any loads issued after the data 380 dependency barrier. 381 382 See the "Examples of memory barrier sequences" subsection for diagrams 383 showing the ordering constraints. 384 385 [!] Note that the first load really has to have a _data_ dependency and 386 not a control dependency. If the address for the second load is dependent 387 on the first load, but the dependency is through a conditional rather than 388 actually loading the address itself, then it's a _control_ dependency and 389 a full read barrier or better is required. See the "Control dependencies" 390 subsection for more information. 391 392 [!] Note that data dependency barriers should normally be paired with 393 write barriers; see the "SMP barrier pairing" subsection. 394 395 396 (3) Read (or load) memory barriers. 397 398 A read barrier is a data dependency barrier plus a guarantee that all the 399 LOAD operations specified before the barrier will appear to happen before 400 all the LOAD operations specified after the barrier with respect to the 401 other components of the system. 402 403 A read barrier is a partial ordering on loads only; it is not required to 404 have any effect on stores. 405 406 Read memory barriers imply data dependency barriers, and so can substitute 407 for them. 408 409 [!] Note that read barriers should normally be paired with write barriers; 410 see the "SMP barrier pairing" subsection. 411 412 413 (4) General memory barriers. 414 415 A general memory barrier gives a guarantee that all the LOAD and STORE 416 operations specified before the barrier will appear to happen before all 417 the LOAD and STORE operations specified after the barrier with respect to 418 the other components of the system. 419 420 A general memory barrier is a partial ordering over both loads and stores. 421 422 General memory barriers imply both read and write memory barriers, and so 423 can substitute for either. 424 425 426 And a couple of implicit varieties: 427 428 (5) ACQUIRE operations. 429 430 This acts as a one-way permeable barrier. It guarantees that all memory 431 operations after the ACQUIRE operation will appear to happen after the 432 ACQUIRE operation with respect to the other components of the system. 433 ACQUIRE operations include LOCK operations and smp_load_acquire() 434 operations. 435 436 Memory operations that occur before an ACQUIRE operation may appear to 437 happen after it completes. 438 439 An ACQUIRE operation should almost always be paired with a RELEASE 440 operation. 441 442 443 (6) RELEASE operations. 444 445 This also acts as a one-way permeable barrier. It guarantees that all 446 memory operations before the RELEASE operation will appear to happen 447 before the RELEASE operation with respect to the other components of the 448 system. RELEASE operations include UNLOCK operations and 449 smp_store_release() operations. 450 451 Memory operations that occur after a RELEASE operation may appear to 452 happen before it completes. 453 454 The use of ACQUIRE and RELEASE operations generally precludes the need 455 for other sorts of memory barrier (but note the exceptions mentioned in 456 the subsection "MMIO write barrier"). In addition, a RELEASE+ACQUIRE 457 pair is -not- guaranteed to act as a full memory barrier. However, after 458 an ACQUIRE on a given variable, all memory accesses preceding any prior 459 RELEASE on that same variable are guaranteed to be visible. In other 460 words, within a given variable's critical section, all accesses of all 461 previous critical sections for that variable are guaranteed to have 462 completed. 463 464 This means that ACQUIRE acts as a minimal "acquire" operation and 465 RELEASE acts as a minimal "release" operation. 466 467 468 Memory barriers are only required where there's a possibility of interaction 469 between two CPUs or between a CPU and a device. If it can be guaranteed that 470 there won't be any such interaction in any particular piece of code, then 471 memory barriers are unnecessary in that piece of code. 472 473 474 Note that these are the _minimum_ guarantees. Different architectures may give 475 more substantial guarantees, but they may _not_ be relied upon outside of arch 476 specific code. 477 478 479 WHAT MAY NOT BE ASSUMED ABOUT MEMORY BARRIERS? 480 ---------------------------------------------- 481 482 There are certain things that the Linux kernel memory barriers do not guarantee: 483 484 (*) There is no guarantee that any of the memory accesses specified before a 485 memory barrier will be _complete_ by the completion of a memory barrier 486 instruction; the barrier can be considered to draw a line in that CPU's 487 access queue that accesses of the appropriate type may not cross. 488 489 (*) There is no guarantee that issuing a memory barrier on one CPU will have 490 any direct effect on another CPU or any other hardware in the system. The 491 indirect effect will be the order in which the second CPU sees the effects 492 of the first CPU's accesses occur, but see the next point: 493 494 (*) There is no guarantee that a CPU will see the correct order of effects 495 from a second CPU's accesses, even _if_ the second CPU uses a memory 496 barrier, unless the first CPU _also_ uses a matching memory barrier (see 497 the subsection on "SMP Barrier Pairing"). 498 499 (*) There is no guarantee that some intervening piece of off-the-CPU 500 hardware[*] will not reorder the memory accesses. CPU cache coherency 501 mechanisms should propagate the indirect effects of a memory barrier 502 between CPUs, but might not do so in order. 503 504 [*] For information on bus mastering DMA and coherency please read: 505 506 Documentation/PCI/pci.txt 507 Documentation/DMA-API-HOWTO.txt 508 Documentation/DMA-API.txt 509 510 511 DATA DEPENDENCY BARRIERS 512 ------------------------ 513 514 The usage requirements of data dependency barriers are a little subtle, and 515 it's not always obvious that they're needed. To illustrate, consider the 516 following sequence of events: 517 518 CPU 1 CPU 2 519 =============== =============== 520 { A == 1, B == 2, C = 3, P == &A, Q == &C } 521 B = 4; 522 <write barrier> 523 WRITE_ONCE(P, &B) 524 Q = READ_ONCE(P); 525 D = *Q; 526 527 There's a clear data dependency here, and it would seem that by the end of the 528 sequence, Q must be either &A or &B, and that: 529 530 (Q == &A) implies (D == 1) 531 (Q == &B) implies (D == 4) 532 533 But! CPU 2's perception of P may be updated _before_ its perception of B, thus 534 leading to the following situation: 535 536 (Q == &B) and (D == 2) ???? 537 538 Whilst this may seem like a failure of coherency or causality maintenance, it 539 isn't, and this behaviour can be observed on certain real CPUs (such as the DEC 540 Alpha). 541 542 To deal with this, a data dependency barrier or better must be inserted 543 between the address load and the data load: 544 545 CPU 1 CPU 2 546 =============== =============== 547 { A == 1, B == 2, C = 3, P == &A, Q == &C } 548 B = 4; 549 <write barrier> 550 WRITE_ONCE(P, &B); 551 Q = READ_ONCE(P); 552 <data dependency barrier> 553 D = *Q; 554 555 This enforces the occurrence of one of the two implications, and prevents the 556 third possibility from arising. 557 558 [!] Note that this extremely counterintuitive situation arises most easily on 559 machines with split caches, so that, for example, one cache bank processes 560 even-numbered cache lines and the other bank processes odd-numbered cache 561 lines. The pointer P might be stored in an odd-numbered cache line, and the 562 variable B might be stored in an even-numbered cache line. Then, if the 563 even-numbered bank of the reading CPU's cache is extremely busy while the 564 odd-numbered bank is idle, one can see the new value of the pointer P (&B), 565 but the old value of the variable B (2). 566 567 568 Another example of where data dependency barriers might be required is where a 569 number is read from memory and then used to calculate the index for an array 570 access: 571 572 CPU 1 CPU 2 573 =============== =============== 574 { M[0] == 1, M[1] == 2, M[3] = 3, P == 0, Q == 3 } 575 M[1] = 4; 576 <write barrier> 577 WRITE_ONCE(P, 1); 578 Q = READ_ONCE(P); 579 <data dependency barrier> 580 D = M[Q]; 581 582 583 The data dependency barrier is very important to the RCU system, 584 for example. See rcu_assign_pointer() and rcu_dereference() in 585 include/linux/rcupdate.h. This permits the current target of an RCU'd 586 pointer to be replaced with a new modified target, without the replacement 587 target appearing to be incompletely initialised. 588 589 See also the subsection on "Cache Coherency" for a more thorough example. 590 591 592 CONTROL DEPENDENCIES 593 -------------------- 594 595 A load-load control dependency requires a full read memory barrier, not 596 simply a data dependency barrier to make it work correctly. Consider the 597 following bit of code: 598 599 q = READ_ONCE(a); 600 if (q) { 601 <data dependency barrier> /* BUG: No data dependency!!! */ 602 p = READ_ONCE(b); 603 } 604 605 This will not have the desired effect because there is no actual data 606 dependency, but rather a control dependency that the CPU may short-circuit 607 by attempting to predict the outcome in advance, so that other CPUs see 608 the load from b as having happened before the load from a. In such a 609 case what's actually required is: 610 611 q = READ_ONCE(a); 612 if (q) { 613 <read barrier> 614 p = READ_ONCE(b); 615 } 616 617 However, stores are not speculated. This means that ordering -is- provided 618 for load-store control dependencies, as in the following example: 619 620 q = READ_ONCE_CTRL(a); 621 if (q) { 622 WRITE_ONCE(b, p); 623 } 624 625 Control dependencies pair normally with other types of barriers. That 626 said, please note that READ_ONCE_CTRL() is not optional! Without the 627 READ_ONCE_CTRL(), the compiler might combine the load from 'a' with 628 other loads from 'a', and the store to 'b' with other stores to 'b', 629 with possible highly counterintuitive effects on ordering. 630 631 Worse yet, if the compiler is able to prove (say) that the value of 632 variable 'a' is always non-zero, it would be well within its rights 633 to optimize the original example by eliminating the "if" statement 634 as follows: 635 636 q = a; 637 b = p; /* BUG: Compiler and CPU can both reorder!!! */ 638 639 Finally, the READ_ONCE_CTRL() includes an smp_read_barrier_depends() 640 that DEC Alpha needs in order to respect control depedencies. 641 642 So don't leave out the READ_ONCE_CTRL(). 643 644 It is tempting to try to enforce ordering on identical stores on both 645 branches of the "if" statement as follows: 646 647 q = READ_ONCE_CTRL(a); 648 if (q) { 649 barrier(); 650 WRITE_ONCE(b, p); 651 do_something(); 652 } else { 653 barrier(); 654 WRITE_ONCE(b, p); 655 do_something_else(); 656 } 657 658 Unfortunately, current compilers will transform this as follows at high 659 optimization levels: 660 661 q = READ_ONCE_CTRL(a); 662 barrier(); 663 WRITE_ONCE(b, p); /* BUG: No ordering vs. load from a!!! */ 664 if (q) { 665 /* WRITE_ONCE(b, p); -- moved up, BUG!!! */ 666 do_something(); 667 } else { 668 /* WRITE_ONCE(b, p); -- moved up, BUG!!! */ 669 do_something_else(); 670 } 671 672 Now there is no conditional between the load from 'a' and the store to 673 'b', which means that the CPU is within its rights to reorder them: 674 The conditional is absolutely required, and must be present in the 675 assembly code even after all compiler optimizations have been applied. 676 Therefore, if you need ordering in this example, you need explicit 677 memory barriers, for example, smp_store_release(): 678 679 q = READ_ONCE(a); 680 if (q) { 681 smp_store_release(&b, p); 682 do_something(); 683 } else { 684 smp_store_release(&b, p); 685 do_something_else(); 686 } 687 688 In contrast, without explicit memory barriers, two-legged-if control 689 ordering is guaranteed only when the stores differ, for example: 690 691 q = READ_ONCE_CTRL(a); 692 if (q) { 693 WRITE_ONCE(b, p); 694 do_something(); 695 } else { 696 WRITE_ONCE(b, r); 697 do_something_else(); 698 } 699 700 The initial READ_ONCE_CTRL() is still required to prevent the compiler 701 from proving the value of 'a'. 702 703 In addition, you need to be careful what you do with the local variable 'q', 704 otherwise the compiler might be able to guess the value and again remove 705 the needed conditional. For example: 706 707 q = READ_ONCE_CTRL(a); 708 if (q % MAX) { 709 WRITE_ONCE(b, p); 710 do_something(); 711 } else { 712 WRITE_ONCE(b, r); 713 do_something_else(); 714 } 715 716 If MAX is defined to be 1, then the compiler knows that (q % MAX) is 717 equal to zero, in which case the compiler is within its rights to 718 transform the above code into the following: 719 720 q = READ_ONCE_CTRL(a); 721 WRITE_ONCE(b, p); 722 do_something_else(); 723 724 Given this transformation, the CPU is not required to respect the ordering 725 between the load from variable 'a' and the store to variable 'b'. It is 726 tempting to add a barrier(), but this does not help. The conditional 727 is gone, and the barrier won't bring it back. Therefore, if you are 728 relying on this ordering, you should make sure that MAX is greater than 729 one, perhaps as follows: 730 731 q = READ_ONCE_CTRL(a); 732 BUILD_BUG_ON(MAX <= 1); /* Order load from a with store to b. */ 733 if (q % MAX) { 734 WRITE_ONCE(b, p); 735 do_something(); 736 } else { 737 WRITE_ONCE(b, r); 738 do_something_else(); 739 } 740 741 Please note once again that the stores to 'b' differ. If they were 742 identical, as noted earlier, the compiler could pull this store outside 743 of the 'if' statement. 744 745 You must also be careful not to rely too much on boolean short-circuit 746 evaluation. Consider this example: 747 748 q = READ_ONCE_CTRL(a); 749 if (q || 1 > 0) 750 WRITE_ONCE(b, 1); 751 752 Because the first condition cannot fault and the second condition is 753 always true, the compiler can transform this example as following, 754 defeating control dependency: 755 756 q = READ_ONCE_CTRL(a); 757 WRITE_ONCE(b, 1); 758 759 This example underscores the need to ensure that the compiler cannot 760 out-guess your code. More generally, although READ_ONCE() does force 761 the compiler to actually emit code for a given load, it does not force 762 the compiler to use the results. 763 764 Finally, control dependencies do -not- provide transitivity. This is 765 demonstrated by two related examples, with the initial values of 766 x and y both being zero: 767 768 CPU 0 CPU 1 769 ======================= ======================= 770 r1 = READ_ONCE_CTRL(x); r2 = READ_ONCE_CTRL(y); 771 if (r1 > 0) if (r2 > 0) 772 WRITE_ONCE(y, 1); WRITE_ONCE(x, 1); 773 774 assert(!(r1 == 1 && r2 == 1)); 775 776 The above two-CPU example will never trigger the assert(). However, 777 if control dependencies guaranteed transitivity (which they do not), 778 then adding the following CPU would guarantee a related assertion: 779 780 CPU 2 781 ===================== 782 WRITE_ONCE(x, 2); 783 784 assert(!(r1 == 2 && r2 == 1 && x == 2)); /* FAILS!!! */ 785 786 But because control dependencies do -not- provide transitivity, the above 787 assertion can fail after the combined three-CPU example completes. If you 788 need the three-CPU example to provide ordering, you will need smp_mb() 789 between the loads and stores in the CPU 0 and CPU 1 code fragments, 790 that is, just before or just after the "if" statements. Furthermore, 791 the original two-CPU example is very fragile and should be avoided. 792 793 These two examples are the LB and WWC litmus tests from this paper: 794 http://www.cl.cam.ac.uk/users/pes20/ppc-supplemental/test6.pdf and this 795 site: https://www.cl.cam.ac.uk/~pes20/ppcmem/index.html. 796 797 In summary: 798 799 (*) Control dependencies must be headed by READ_ONCE_CTRL(). 800 Or, as a much less preferable alternative, interpose 801 smp_read_barrier_depends() between a READ_ONCE() and the 802 control-dependent write. 803 804 (*) Control dependencies can order prior loads against later stores. 805 However, they do -not- guarantee any other sort of ordering: 806 Not prior loads against later loads, nor prior stores against 807 later anything. If you need these other forms of ordering, 808 use smp_rmb(), smp_wmb(), or, in the case of prior stores and 809 later loads, smp_mb(). 810 811 (*) If both legs of the "if" statement begin with identical stores 812 to the same variable, a barrier() statement is required at the 813 beginning of each leg of the "if" statement. 814 815 (*) Control dependencies require at least one run-time conditional 816 between the prior load and the subsequent store, and this 817 conditional must involve the prior load. If the compiler is able 818 to optimize the conditional away, it will have also optimized 819 away the ordering. Careful use of READ_ONCE_CTRL() READ_ONCE(), 820 and WRITE_ONCE() can help to preserve the needed conditional. 821 822 (*) Control dependencies require that the compiler avoid reordering the 823 dependency into nonexistence. Careful use of READ_ONCE_CTRL() 824 or smp_read_barrier_depends() can help to preserve your control 825 dependency. Please see the Compiler Barrier section for more 826 information. 827 828 (*) Control dependencies pair normally with other types of barriers. 829 830 (*) Control dependencies do -not- provide transitivity. If you 831 need transitivity, use smp_mb(). 832 833 834 SMP BARRIER PAIRING 835 ------------------- 836 837 When dealing with CPU-CPU interactions, certain types of memory barrier should 838 always be paired. A lack of appropriate pairing is almost certainly an error. 839 840 General barriers pair with each other, though they also pair with most 841 other types of barriers, albeit without transitivity. An acquire barrier 842 pairs with a release barrier, but both may also pair with other barriers, 843 including of course general barriers. A write barrier pairs with a data 844 dependency barrier, a control dependency, an acquire barrier, a release 845 barrier, a read barrier, or a general barrier. Similarly a read barrier, 846 control dependency, or a data dependency barrier pairs with a write 847 barrier, an acquire barrier, a release barrier, or a general barrier: 848 849 CPU 1 CPU 2 850 =============== =============== 851 WRITE_ONCE(a, 1); 852 <write barrier> 853 WRITE_ONCE(b, 2); x = READ_ONCE(b); 854 <read barrier> 855 y = READ_ONCE(a); 856 857 Or: 858 859 CPU 1 CPU 2 860 =============== =============================== 861 a = 1; 862 <write barrier> 863 WRITE_ONCE(b, &a); x = READ_ONCE(b); 864 <data dependency barrier> 865 y = *x; 866 867 Or even: 868 869 CPU 1 CPU 2 870 =============== =============================== 871 r1 = READ_ONCE(y); 872 <general barrier> 873 WRITE_ONCE(y, 1); if (r2 = READ_ONCE(x)) { 874 <implicit control dependency> 875 WRITE_ONCE(y, 1); 876 } 877 878 assert(r1 == 0 || r2 == 0); 879 880 Basically, the read barrier always has to be there, even though it can be of 881 the "weaker" type. 882 883 [!] Note that the stores before the write barrier would normally be expected to 884 match the loads after the read barrier or the data dependency barrier, and vice 885 versa: 886 887 CPU 1 CPU 2 888 =================== =================== 889 WRITE_ONCE(a, 1); }---- --->{ v = READ_ONCE(c); 890 WRITE_ONCE(b, 2); } \ / { w = READ_ONCE(d); 891 <write barrier> \ <read barrier> 892 WRITE_ONCE(c, 3); } / \ { x = READ_ONCE(a); 893 WRITE_ONCE(d, 4); }---- --->{ y = READ_ONCE(b); 894 895 896 EXAMPLES OF MEMORY BARRIER SEQUENCES 897 ------------------------------------ 898 899 Firstly, write barriers act as partial orderings on store operations. 900 Consider the following sequence of events: 901 902 CPU 1 903 ======================= 904 STORE A = 1 905 STORE B = 2 906 STORE C = 3 907 <write barrier> 908 STORE D = 4 909 STORE E = 5 910 911 This sequence of events is committed to the memory coherence system in an order 912 that the rest of the system might perceive as the unordered set of { STORE A, 913 STORE B, STORE C } all occurring before the unordered set of { STORE D, STORE E 914 }: 915 916 +-------+ : : 917 | | +------+ 918 | |------>| C=3 | } /\ 919 | | : +------+ }----- \ -----> Events perceptible to 920 | | : | A=1 | } \/ the rest of the system 921 | | : +------+ } 922 | CPU 1 | : | B=2 | } 923 | | +------+ } 924 | | wwwwwwwwwwwwwwww } <--- At this point the write barrier 925 | | +------+ } requires all stores prior to the 926 | | : | E=5 | } barrier to be committed before 927 | | : +------+ } further stores may take place 928 | |------>| D=4 | } 929 | | +------+ 930 +-------+ : : 931 | 932 | Sequence in which stores are committed to the 933 | memory system by CPU 1 934 V 935 936 937 Secondly, data dependency barriers act as partial orderings on data-dependent 938 loads. Consider the following sequence of events: 939 940 CPU 1 CPU 2 941 ======================= ======================= 942 { B = 7; X = 9; Y = 8; C = &Y } 943 STORE A = 1 944 STORE B = 2 945 <write barrier> 946 STORE C = &B LOAD X 947 STORE D = 4 LOAD C (gets &B) 948 LOAD *C (reads B) 949 950 Without intervention, CPU 2 may perceive the events on CPU 1 in some 951 effectively random order, despite the write barrier issued by CPU 1: 952 953 +-------+ : : : : 954 | | +------+ +-------+ | Sequence of update 955 | |------>| B=2 |----- --->| Y->8 | | of perception on 956 | | : +------+ \ +-------+ | CPU 2 957 | CPU 1 | : | A=1 | \ --->| C->&Y | V 958 | | +------+ | +-------+ 959 | | wwwwwwwwwwwwwwww | : : 960 | | +------+ | : : 961 | | : | C=&B |--- | : : +-------+ 962 | | : +------+ \ | +-------+ | | 963 | |------>| D=4 | ----------->| C->&B |------>| | 964 | | +------+ | +-------+ | | 965 +-------+ : : | : : | | 966 | : : | | 967 | : : | CPU 2 | 968 | +-------+ | | 969 Apparently incorrect ---> | | B->7 |------>| | 970 perception of B (!) | +-------+ | | 971 | : : | | 972 | +-------+ | | 973 The load of X holds ---> \ | X->9 |------>| | 974 up the maintenance \ +-------+ | | 975 of coherence of B ----->| B->2 | +-------+ 976 +-------+ 977 : : 978 979 980 In the above example, CPU 2 perceives that B is 7, despite the load of *C 981 (which would be B) coming after the LOAD of C. 982 983 If, however, a data dependency barrier were to be placed between the load of C 984 and the load of *C (ie: B) on CPU 2: 985 986 CPU 1 CPU 2 987 ======================= ======================= 988 { B = 7; X = 9; Y = 8; C = &Y } 989 STORE A = 1 990 STORE B = 2 991 <write barrier> 992 STORE C = &B LOAD X 993 STORE D = 4 LOAD C (gets &B) 994 <data dependency barrier> 995 LOAD *C (reads B) 996 997 then the following will occur: 998 999 +-------+ : : : : 1000 | | +------+ +-------+ 1001 | |------>| B=2 |----- --->| Y->8 | 1002 | | : +------+ \ +-------+ 1003 | CPU 1 | : | A=1 | \ --->| C->&Y | 1004 | | +------+ | +-------+ 1005 | | wwwwwwwwwwwwwwww | : : 1006 | | +------+ | : : 1007 | | : | C=&B |--- | : : +-------+ 1008 | | : +------+ \ | +-------+ | | 1009 | |------>| D=4 | ----------->| C->&B |------>| | 1010 | | +------+ | +-------+ | | 1011 +-------+ : : | : : | | 1012 | : : | | 1013 | : : | CPU 2 | 1014 | +-------+ | | 1015 | | X->9 |------>| | 1016 | +-------+ | | 1017 Makes sure all effects ---> \ ddddddddddddddddd | | 1018 prior to the store of C \ +-------+ | | 1019 are perceptible to ----->| B->2 |------>| | 1020 subsequent loads +-------+ | | 1021 : : +-------+ 1022 1023 1024 And thirdly, a read barrier acts as a partial order on loads. Consider the 1025 following sequence of events: 1026 1027 CPU 1 CPU 2 1028 ======================= ======================= 1029 { A = 0, B = 9 } 1030 STORE A=1 1031 <write barrier> 1032 STORE B=2 1033 LOAD B 1034 LOAD A 1035 1036 Without intervention, CPU 2 may then choose to perceive the events on CPU 1 in 1037 some effectively random order, despite the write barrier issued by CPU 1: 1038 1039 +-------+ : : : : 1040 | | +------+ +-------+ 1041 | |------>| A=1 |------ --->| A->0 | 1042 | | +------+ \ +-------+ 1043 | CPU 1 | wwwwwwwwwwwwwwww \ --->| B->9 | 1044 | | +------+ | +-------+ 1045 | |------>| B=2 |--- | : : 1046 | | +------+ \ | : : +-------+ 1047 +-------+ : : \ | +-------+ | | 1048 ---------->| B->2 |------>| | 1049 | +-------+ | CPU 2 | 1050 | | A->0 |------>| | 1051 | +-------+ | | 1052 | : : +-------+ 1053 \ : : 1054 \ +-------+ 1055 ---->| A->1 | 1056 +-------+ 1057 : : 1058 1059 1060 If, however, a read barrier were to be placed between the load of B and the 1061 load of A on CPU 2: 1062 1063 CPU 1 CPU 2 1064 ======================= ======================= 1065 { A = 0, B = 9 } 1066 STORE A=1 1067 <write barrier> 1068 STORE B=2 1069 LOAD B 1070 <read barrier> 1071 LOAD A 1072 1073 then the partial ordering imposed by CPU 1 will be perceived correctly by CPU 1074 2: 1075 1076 +-------+ : : : : 1077 | | +------+ +-------+ 1078 | |------>| A=1 |------ --->| A->0 | 1079 | | +------+ \ +-------+ 1080 | CPU 1 | wwwwwwwwwwwwwwww \ --->| B->9 | 1081 | | +------+ | +-------+ 1082 | |------>| B=2 |--- | : : 1083 | | +------+ \ | : : +-------+ 1084 +-------+ : : \ | +-------+ | | 1085 ---------->| B->2 |------>| | 1086 | +-------+ | CPU 2 | 1087 | : : | | 1088 | : : | | 1089 At this point the read ----> \ rrrrrrrrrrrrrrrrr | | 1090 barrier causes all effects \ +-------+ | | 1091 prior to the storage of B ---->| A->1 |------>| | 1092 to be perceptible to CPU 2 +-------+ | | 1093 : : +-------+ 1094 1095 1096 To illustrate this more completely, consider what could happen if the code 1097 contained a load of A either side of the read barrier: 1098 1099 CPU 1 CPU 2 1100 ======================= ======================= 1101 { A = 0, B = 9 } 1102 STORE A=1 1103 <write barrier> 1104 STORE B=2 1105 LOAD B 1106 LOAD A [first load of A] 1107 <read barrier> 1108 LOAD A [second load of A] 1109 1110 Even though the two loads of A both occur after the load of B, they may both 1111 come up with different values: 1112 1113 +-------+ : : : : 1114 | | +------+ +-------+ 1115 | |------>| A=1 |------ --->| A->0 | 1116 | | +------+ \ +-------+ 1117 | CPU 1 | wwwwwwwwwwwwwwww \ --->| B->9 | 1118 | | +------+ | +-------+ 1119 | |------>| B=2 |--- | : : 1120 | | +------+ \ | : : +-------+ 1121 +-------+ : : \ | +-------+ | | 1122 ---------->| B->2 |------>| | 1123 | +-------+ | CPU 2 | 1124 | : : | | 1125 | : : | | 1126 | +-------+ | | 1127 | | A->0 |------>| 1st | 1128 | +-------+ | | 1129 At this point the read ----> \ rrrrrrrrrrrrrrrrr | | 1130 barrier causes all effects \ +-------+ | | 1131 prior to the storage of B ---->| A->1 |------>| 2nd | 1132 to be perceptible to CPU 2 +-------+ | | 1133 : : +-------+ 1134 1135 1136 But it may be that the update to A from CPU 1 becomes perceptible to CPU 2 1137 before the read barrier completes anyway: 1138 1139 +-------+ : : : : 1140 | | +------+ +-------+ 1141 | |------>| A=1 |------ --->| A->0 | 1142 | | +------+ \ +-------+ 1143 | CPU 1 | wwwwwwwwwwwwwwww \ --->| B->9 | 1144 | | +------+ | +-------+ 1145 | |------>| B=2 |--- | : : 1146 | | +------+ \ | : : +-------+ 1147 +-------+ : : \ | +-------+ | | 1148 ---------->| B->2 |------>| | 1149 | +-------+ | CPU 2 | 1150 | : : | | 1151 \ : : | | 1152 \ +-------+ | | 1153 ---->| A->1 |------>| 1st | 1154 +-------+ | | 1155 rrrrrrrrrrrrrrrrr | | 1156 +-------+ | | 1157 | A->1 |------>| 2nd | 1158 +-------+ | | 1159 : : +-------+ 1160 1161 1162 The guarantee is that the second load will always come up with A == 1 if the 1163 load of B came up with B == 2. No such guarantee exists for the first load of 1164 A; that may come up with either A == 0 or A == 1. 1165 1166 1167 READ MEMORY BARRIERS VS LOAD SPECULATION 1168 ---------------------------------------- 1169 1170 Many CPUs speculate with loads: that is they see that they will need to load an 1171 item from memory, and they find a time where they're not using the bus for any 1172 other loads, and so do the load in advance - even though they haven't actually 1173 got to that point in the instruction execution flow yet. This permits the 1174 actual load instruction to potentially complete immediately because the CPU 1175 already has the value to hand. 1176 1177 It may turn out that the CPU didn't actually need the value - perhaps because a 1178 branch circumvented the load - in which case it can discard the value or just 1179 cache it for later use. 1180 1181 Consider: 1182 1183 CPU 1 CPU 2 1184 ======================= ======================= 1185 LOAD B 1186 DIVIDE } Divide instructions generally 1187 DIVIDE } take a long time to perform 1188 LOAD A 1189 1190 Which might appear as this: 1191 1192 : : +-------+ 1193 +-------+ | | 1194 --->| B->2 |------>| | 1195 +-------+ | CPU 2 | 1196 : :DIVIDE | | 1197 +-------+ | | 1198 The CPU being busy doing a ---> --->| A->0 |~~~~ | | 1199 division speculates on the +-------+ ~ | | 1200 LOAD of A : : ~ | | 1201 : :DIVIDE | | 1202 : : ~ | | 1203 Once the divisions are complete --> : : ~-->| | 1204 the CPU can then perform the : : | | 1205 LOAD with immediate effect : : +-------+ 1206 1207 1208 Placing a read barrier or a data dependency barrier just before the second 1209 load: 1210 1211 CPU 1 CPU 2 1212 ======================= ======================= 1213 LOAD B 1214 DIVIDE 1215 DIVIDE 1216 <read barrier> 1217 LOAD A 1218 1219 will force any value speculatively obtained to be reconsidered to an extent 1220 dependent on the type of barrier used. If there was no change made to the 1221 speculated memory location, then the speculated value will just be used: 1222 1223 : : +-------+ 1224 +-------+ | | 1225 --->| B->2 |------>| | 1226 +-------+ | CPU 2 | 1227 : :DIVIDE | | 1228 +-------+ | | 1229 The CPU being busy doing a ---> --->| A->0 |~~~~ | | 1230 division speculates on the +-------+ ~ | | 1231 LOAD of A : : ~ | | 1232 : :DIVIDE | | 1233 : : ~ | | 1234 : : ~ | | 1235 rrrrrrrrrrrrrrrr~ | | 1236 : : ~ | | 1237 : : ~-->| | 1238 : : | | 1239 : : +-------+ 1240 1241 1242 but if there was an update or an invalidation from another CPU pending, then 1243 the speculation will be cancelled and the value reloaded: 1244 1245 : : +-------+ 1246 +-------+ | | 1247 --->| B->2 |------>| | 1248 +-------+ | CPU 2 | 1249 : :DIVIDE | | 1250 +-------+ | | 1251 The CPU being busy doing a ---> --->| A->0 |~~~~ | | 1252 division speculates on the +-------+ ~ | | 1253 LOAD of A : : ~ | | 1254 : :DIVIDE | | 1255 : : ~ | | 1256 : : ~ | | 1257 rrrrrrrrrrrrrrrrr | | 1258 +-------+ | | 1259 The speculation is discarded ---> --->| A->1 |------>| | 1260 and an updated value is +-------+ | | 1261 retrieved : : +-------+ 1262 1263 1264 TRANSITIVITY 1265 ------------ 1266 1267 Transitivity is a deeply intuitive notion about ordering that is not 1268 always provided by real computer systems. The following example 1269 demonstrates transitivity (also called "cumulativity"): 1270 1271 CPU 1 CPU 2 CPU 3 1272 ======================= ======================= ======================= 1273 { X = 0, Y = 0 } 1274 STORE X=1 LOAD X STORE Y=1 1275 <general barrier> <general barrier> 1276 LOAD Y LOAD X 1277 1278 Suppose that CPU 2's load from X returns 1 and its load from Y returns 0. 1279 This indicates that CPU 2's load from X in some sense follows CPU 1's 1280 store to X and that CPU 2's load from Y in some sense preceded CPU 3's 1281 store to Y. The question is then "Can CPU 3's load from X return 0?" 1282 1283 Because CPU 2's load from X in some sense came after CPU 1's store, it 1284 is natural to expect that CPU 3's load from X must therefore return 1. 1285 This expectation is an example of transitivity: if a load executing on 1286 CPU A follows a load from the same variable executing on CPU B, then 1287 CPU A's load must either return the same value that CPU B's load did, 1288 or must return some later value. 1289 1290 In the Linux kernel, use of general memory barriers guarantees 1291 transitivity. Therefore, in the above example, if CPU 2's load from X 1292 returns 1 and its load from Y returns 0, then CPU 3's load from X must 1293 also return 1. 1294 1295 However, transitivity is -not- guaranteed for read or write barriers. 1296 For example, suppose that CPU 2's general barrier in the above example 1297 is changed to a read barrier as shown below: 1298 1299 CPU 1 CPU 2 CPU 3 1300 ======================= ======================= ======================= 1301 { X = 0, Y = 0 } 1302 STORE X=1 LOAD X STORE Y=1 1303 <read barrier> <general barrier> 1304 LOAD Y LOAD X 1305 1306 This substitution destroys transitivity: in this example, it is perfectly 1307 legal for CPU 2's load from X to return 1, its load from Y to return 0, 1308 and CPU 3's load from X to return 0. 1309 1310 The key point is that although CPU 2's read barrier orders its pair 1311 of loads, it does not guarantee to order CPU 1's store. Therefore, if 1312 this example runs on a system where CPUs 1 and 2 share a store buffer 1313 or a level of cache, CPU 2 might have early access to CPU 1's writes. 1314 General barriers are therefore required to ensure that all CPUs agree 1315 on the combined order of CPU 1's and CPU 2's accesses. 1316 1317 To reiterate, if your code requires transitivity, use general barriers 1318 throughout. 1319 1320 1321 ======================== 1322 EXPLICIT KERNEL BARRIERS 1323 ======================== 1324 1325 The Linux kernel has a variety of different barriers that act at different 1326 levels: 1327 1328 (*) Compiler barrier. 1329 1330 (*) CPU memory barriers. 1331 1332 (*) MMIO write barrier. 1333 1334 1335 COMPILER BARRIER 1336 ---------------- 1337 1338 The Linux kernel has an explicit compiler barrier function that prevents the 1339 compiler from moving the memory accesses either side of it to the other side: 1340 1341 barrier(); 1342 1343 This is a general barrier -- there are no read-read or write-write 1344 variants of barrier(). However, READ_ONCE() and WRITE_ONCE() can be 1345 thought of as weak forms of barrier() that affect only the specific 1346 accesses flagged by the READ_ONCE() or WRITE_ONCE(). 1347 1348 The barrier() function has the following effects: 1349 1350 (*) Prevents the compiler from reordering accesses following the 1351 barrier() to precede any accesses preceding the barrier(). 1352 One example use for this property is to ease communication between 1353 interrupt-handler code and the code that was interrupted. 1354 1355 (*) Within a loop, forces the compiler to load the variables used 1356 in that loop's conditional on each pass through that loop. 1357 1358 The READ_ONCE() and WRITE_ONCE() functions can prevent any number of 1359 optimizations that, while perfectly safe in single-threaded code, can 1360 be fatal in concurrent code. Here are some examples of these sorts 1361 of optimizations: 1362 1363 (*) The compiler is within its rights to reorder loads and stores 1364 to the same variable, and in some cases, the CPU is within its 1365 rights to reorder loads to the same variable. This means that 1366 the following code: 1367 1368 a[0] = x; 1369 a[1] = x; 1370 1371 Might result in an older value of x stored in a[1] than in a[0]. 1372 Prevent both the compiler and the CPU from doing this as follows: 1373 1374 a[0] = READ_ONCE(x); 1375 a[1] = READ_ONCE(x); 1376 1377 In short, READ_ONCE() and WRITE_ONCE() provide cache coherence for 1378 accesses from multiple CPUs to a single variable. 1379 1380 (*) The compiler is within its rights to merge successive loads from 1381 the same variable. Such merging can cause the compiler to "optimize" 1382 the following code: 1383 1384 while (tmp = a) 1385 do_something_with(tmp); 1386 1387 into the following code, which, although in some sense legitimate 1388 for single-threaded code, is almost certainly not what the developer 1389 intended: 1390 1391 if (tmp = a) 1392 for (;;) 1393 do_something_with(tmp); 1394 1395 Use READ_ONCE() to prevent the compiler from doing this to you: 1396 1397 while (tmp = READ_ONCE(a)) 1398 do_something_with(tmp); 1399 1400 (*) The compiler is within its rights to reload a variable, for example, 1401 in cases where high register pressure prevents the compiler from 1402 keeping all data of interest in registers. The compiler might 1403 therefore optimize the variable 'tmp' out of our previous example: 1404 1405 while (tmp = a) 1406 do_something_with(tmp); 1407 1408 This could result in the following code, which is perfectly safe in 1409 single-threaded code, but can be fatal in concurrent code: 1410 1411 while (a) 1412 do_something_with(a); 1413 1414 For example, the optimized version of this code could result in 1415 passing a zero to do_something_with() in the case where the variable 1416 a was modified by some other CPU between the "while" statement and 1417 the call to do_something_with(). 1418 1419 Again, use READ_ONCE() to prevent the compiler from doing this: 1420 1421 while (tmp = READ_ONCE(a)) 1422 do_something_with(tmp); 1423 1424 Note that if the compiler runs short of registers, it might save 1425 tmp onto the stack. The overhead of this saving and later restoring 1426 is why compilers reload variables. Doing so is perfectly safe for 1427 single-threaded code, so you need to tell the compiler about cases 1428 where it is not safe. 1429 1430 (*) The compiler is within its rights to omit a load entirely if it knows 1431 what the value will be. For example, if the compiler can prove that 1432 the value of variable 'a' is always zero, it can optimize this code: 1433 1434 while (tmp = a) 1435 do_something_with(tmp); 1436 1437 Into this: 1438 1439 do { } while (0); 1440 1441 This transformation is a win for single-threaded code because it 1442 gets rid of a load and a branch. The problem is that the compiler 1443 will carry out its proof assuming that the current CPU is the only 1444 one updating variable 'a'. If variable 'a' is shared, then the 1445 compiler's proof will be erroneous. Use READ_ONCE() to tell the 1446 compiler that it doesn't know as much as it thinks it does: 1447 1448 while (tmp = READ_ONCE(a)) 1449 do_something_with(tmp); 1450 1451 But please note that the compiler is also closely watching what you 1452 do with the value after the READ_ONCE(). For example, suppose you 1453 do the following and MAX is a preprocessor macro with the value 1: 1454 1455 while ((tmp = READ_ONCE(a)) % MAX) 1456 do_something_with(tmp); 1457 1458 Then the compiler knows that the result of the "%" operator applied 1459 to MAX will always be zero, again allowing the compiler to optimize 1460 the code into near-nonexistence. (It will still load from the 1461 variable 'a'.) 1462 1463 (*) Similarly, the compiler is within its rights to omit a store entirely 1464 if it knows that the variable already has the value being stored. 1465 Again, the compiler assumes that the current CPU is the only one 1466 storing into the variable, which can cause the compiler to do the 1467 wrong thing for shared variables. For example, suppose you have 1468 the following: 1469 1470 a = 0; 1471 /* Code that does not store to variable a. */ 1472 a = 0; 1473 1474 The compiler sees that the value of variable 'a' is already zero, so 1475 it might well omit the second store. This would come as a fatal 1476 surprise if some other CPU might have stored to variable 'a' in the 1477 meantime. 1478 1479 Use WRITE_ONCE() to prevent the compiler from making this sort of 1480 wrong guess: 1481 1482 WRITE_ONCE(a, 0); 1483 /* Code that does not store to variable a. */ 1484 WRITE_ONCE(a, 0); 1485 1486 (*) The compiler is within its rights to reorder memory accesses unless 1487 you tell it not to. For example, consider the following interaction 1488 between process-level code and an interrupt handler: 1489 1490 void process_level(void) 1491 { 1492 msg = get_message(); 1493 flag = true; 1494 } 1495 1496 void interrupt_handler(void) 1497 { 1498 if (flag) 1499 process_message(msg); 1500 } 1501 1502 There is nothing to prevent the compiler from transforming 1503 process_level() to the following, in fact, this might well be a 1504 win for single-threaded code: 1505 1506 void process_level(void) 1507 { 1508 flag = true; 1509 msg = get_message(); 1510 } 1511 1512 If the interrupt occurs between these two statement, then 1513 interrupt_handler() might be passed a garbled msg. Use WRITE_ONCE() 1514 to prevent this as follows: 1515 1516 void process_level(void) 1517 { 1518 WRITE_ONCE(msg, get_message()); 1519 WRITE_ONCE(flag, true); 1520 } 1521 1522 void interrupt_handler(void) 1523 { 1524 if (READ_ONCE(flag)) 1525 process_message(READ_ONCE(msg)); 1526 } 1527 1528 Note that the READ_ONCE() and WRITE_ONCE() wrappers in 1529 interrupt_handler() are needed if this interrupt handler can itself 1530 be interrupted by something that also accesses 'flag' and 'msg', 1531 for example, a nested interrupt or an NMI. Otherwise, READ_ONCE() 1532 and WRITE_ONCE() are not needed in interrupt_handler() other than 1533 for documentation purposes. (Note also that nested interrupts 1534 do not typically occur in modern Linux kernels, in fact, if an 1535 interrupt handler returns with interrupts enabled, you will get a 1536 WARN_ONCE() splat.) 1537 1538 You should assume that the compiler can move READ_ONCE() and 1539 WRITE_ONCE() past code not containing READ_ONCE(), WRITE_ONCE(), 1540 barrier(), or similar primitives. 1541 1542 This effect could also be achieved using barrier(), but READ_ONCE() 1543 and WRITE_ONCE() are more selective: With READ_ONCE() and 1544 WRITE_ONCE(), the compiler need only forget the contents of the 1545 indicated memory locations, while with barrier() the compiler must 1546 discard the value of all memory locations that it has currented 1547 cached in any machine registers. Of course, the compiler must also 1548 respect the order in which the READ_ONCE()s and WRITE_ONCE()s occur, 1549 though the CPU of course need not do so. 1550 1551 (*) The compiler is within its rights to invent stores to a variable, 1552 as in the following example: 1553 1554 if (a) 1555 b = a; 1556 else 1557 b = 42; 1558 1559 The compiler might save a branch by optimizing this as follows: 1560 1561 b = 42; 1562 if (a) 1563 b = a; 1564 1565 In single-threaded code, this is not only safe, but also saves 1566 a branch. Unfortunately, in concurrent code, this optimization 1567 could cause some other CPU to see a spurious value of 42 -- even 1568 if variable 'a' was never zero -- when loading variable 'b'. 1569 Use WRITE_ONCE() to prevent this as follows: 1570 1571 if (a) 1572 WRITE_ONCE(b, a); 1573 else 1574 WRITE_ONCE(b, 42); 1575 1576 The compiler can also invent loads. These are usually less 1577 damaging, but they can result in cache-line bouncing and thus in 1578 poor performance and scalability. Use READ_ONCE() to prevent 1579 invented loads. 1580 1581 (*) For aligned memory locations whose size allows them to be accessed 1582 with a single memory-reference instruction, prevents "load tearing" 1583 and "store tearing," in which a single large access is replaced by 1584 multiple smaller accesses. For example, given an architecture having 1585 16-bit store instructions with 7-bit immediate fields, the compiler 1586 might be tempted to use two 16-bit store-immediate instructions to 1587 implement the following 32-bit store: 1588 1589 p = 0x00010002; 1590 1591 Please note that GCC really does use this sort of optimization, 1592 which is not surprising given that it would likely take more 1593 than two instructions to build the constant and then store it. 1594 This optimization can therefore be a win in single-threaded code. 1595 In fact, a recent bug (since fixed) caused GCC to incorrectly use 1596 this optimization in a volatile store. In the absence of such bugs, 1597 use of WRITE_ONCE() prevents store tearing in the following example: 1598 1599 WRITE_ONCE(p, 0x00010002); 1600 1601 Use of packed structures can also result in load and store tearing, 1602 as in this example: 1603 1604 struct __attribute__((__packed__)) foo { 1605 short a; 1606 int b; 1607 short c; 1608 }; 1609 struct foo foo1, foo2; 1610 ... 1611 1612 foo2.a = foo1.a; 1613 foo2.b = foo1.b; 1614 foo2.c = foo1.c; 1615 1616 Because there are no READ_ONCE() or WRITE_ONCE() wrappers and no 1617 volatile markings, the compiler would be well within its rights to 1618 implement these three assignment statements as a pair of 32-bit 1619 loads followed by a pair of 32-bit stores. This would result in 1620 load tearing on 'foo1.b' and store tearing on 'foo2.b'. READ_ONCE() 1621 and WRITE_ONCE() again prevent tearing in this example: 1622 1623 foo2.a = foo1.a; 1624 WRITE_ONCE(foo2.b, READ_ONCE(foo1.b)); 1625 foo2.c = foo1.c; 1626 1627 All that aside, it is never necessary to use READ_ONCE() and 1628 WRITE_ONCE() on a variable that has been marked volatile. For example, 1629 because 'jiffies' is marked volatile, it is never necessary to 1630 say READ_ONCE(jiffies). The reason for this is that READ_ONCE() and 1631 WRITE_ONCE() are implemented as volatile casts, which has no effect when 1632 its argument is already marked volatile. 1633 1634 Please note that these compiler barriers have no direct effect on the CPU, 1635 which may then reorder things however it wishes. 1636 1637 1638 CPU MEMORY BARRIERS 1639 ------------------- 1640 1641 The Linux kernel has eight basic CPU memory barriers: 1642 1643 TYPE MANDATORY SMP CONDITIONAL 1644 =============== ======================= =========================== 1645 GENERAL mb() smp_mb() 1646 WRITE wmb() smp_wmb() 1647 READ rmb() smp_rmb() 1648 DATA DEPENDENCY read_barrier_depends() smp_read_barrier_depends() 1649 1650 1651 All memory barriers except the data dependency barriers imply a compiler 1652 barrier. Data dependencies do not impose any additional compiler ordering. 1653 1654 Aside: In the case of data dependencies, the compiler would be expected 1655 to issue the loads in the correct order (eg. `a[b]` would have to load 1656 the value of b before loading a[b]), however there is no guarantee in 1657 the C specification that the compiler may not speculate the value of b 1658 (eg. is equal to 1) and load a before b (eg. tmp = a[1]; if (b != 1) 1659 tmp = a[b]; ). There is also the problem of a compiler reloading b after 1660 having loaded a[b], thus having a newer copy of b than a[b]. A consensus 1661 has not yet been reached about these problems, however the READ_ONCE() 1662 macro is a good place to start looking. 1663 1664 SMP memory barriers are reduced to compiler barriers on uniprocessor compiled 1665 systems because it is assumed that a CPU will appear to be self-consistent, 1666 and will order overlapping accesses correctly with respect to itself. 1667 1668 [!] Note that SMP memory barriers _must_ be used to control the ordering of 1669 references to shared memory on SMP systems, though the use of locking instead 1670 is sufficient. 1671 1672 Mandatory barriers should not be used to control SMP effects, since mandatory 1673 barriers unnecessarily impose overhead on UP systems. They may, however, be 1674 used to control MMIO effects on accesses through relaxed memory I/O windows. 1675 These are required even on non-SMP systems as they affect the order in which 1676 memory operations appear to a device by prohibiting both the compiler and the 1677 CPU from reordering them. 1678 1679 1680 There are some more advanced barrier functions: 1681 1682 (*) smp_store_mb(var, value) 1683 1684 This assigns the value to the variable and then inserts a full memory 1685 barrier after it, depending on the function. It isn't guaranteed to 1686 insert anything more than a compiler barrier in a UP compilation. 1687 1688 1689 (*) smp_mb__before_atomic(); 1690 (*) smp_mb__after_atomic(); 1691 1692 These are for use with atomic (such as add, subtract, increment and 1693 decrement) functions that don't return a value, especially when used for 1694 reference counting. These functions do not imply memory barriers. 1695 1696 These are also used for atomic bitop functions that do not return a 1697 value (such as set_bit and clear_bit). 1698 1699 As an example, consider a piece of code that marks an object as being dead 1700 and then decrements the object's reference count: 1701 1702 obj->dead = 1; 1703 smp_mb__before_atomic(); 1704 atomic_dec(&obj->ref_count); 1705 1706 This makes sure that the death mark on the object is perceived to be set 1707 *before* the reference counter is decremented. 1708 1709 See Documentation/atomic_ops.txt for more information. See the "Atomic 1710 operations" subsection for information on where to use these. 1711 1712 1713 (*) dma_wmb(); 1714 (*) dma_rmb(); 1715 1716 These are for use with consistent memory to guarantee the ordering 1717 of writes or reads of shared memory accessible to both the CPU and a 1718 DMA capable device. 1719 1720 For example, consider a device driver that shares memory with a device 1721 and uses a descriptor status value to indicate if the descriptor belongs 1722 to the device or the CPU, and a doorbell to notify it when new 1723 descriptors are available: 1724 1725 if (desc->status != DEVICE_OWN) { 1726 /* do not read data until we own descriptor */ 1727 dma_rmb(); 1728 1729 /* read/modify data */ 1730 read_data = desc->data; 1731 desc->data = write_data; 1732 1733 /* flush modifications before status update */ 1734 dma_wmb(); 1735 1736 /* assign ownership */ 1737 desc->status = DEVICE_OWN; 1738 1739 /* force memory to sync before notifying device via MMIO */ 1740 wmb(); 1741 1742 /* notify device of new descriptors */ 1743 writel(DESC_NOTIFY, doorbell); 1744 } 1745 1746 The dma_rmb() allows us guarantee the device has released ownership 1747 before we read the data from the descriptor, and the dma_wmb() allows 1748 us to guarantee the data is written to the descriptor before the device 1749 can see it now has ownership. The wmb() is needed to guarantee that the 1750 cache coherent memory writes have completed before attempting a write to 1751 the cache incoherent MMIO region. 1752 1753 See Documentation/DMA-API.txt for more information on consistent memory. 1754 1755 MMIO WRITE BARRIER 1756 ------------------ 1757 1758 The Linux kernel also has a special barrier for use with memory-mapped I/O 1759 writes: 1760 1761 mmiowb(); 1762 1763 This is a variation on the mandatory write barrier that causes writes to weakly 1764 ordered I/O regions to be partially ordered. Its effects may go beyond the 1765 CPU->Hardware interface and actually affect the hardware at some level. 1766 1767 See the subsection "Locks vs I/O accesses" for more information. 1768 1769 1770 =============================== 1771 IMPLICIT KERNEL MEMORY BARRIERS 1772 =============================== 1773 1774 Some of the other functions in the linux kernel imply memory barriers, amongst 1775 which are locking and scheduling functions. 1776 1777 This specification is a _minimum_ guarantee; any particular architecture may 1778 provide more substantial guarantees, but these may not be relied upon outside 1779 of arch specific code. 1780 1781 1782 ACQUIRING FUNCTIONS 1783 ------------------- 1784 1785 The Linux kernel has a number of locking constructs: 1786 1787 (*) spin locks 1788 (*) R/W spin locks 1789 (*) mutexes 1790 (*) semaphores 1791 (*) R/W semaphores 1792 (*) RCU 1793 1794 In all cases there are variants on "ACQUIRE" operations and "RELEASE" operations 1795 for each construct. These operations all imply certain barriers: 1796 1797 (1) ACQUIRE operation implication: 1798 1799 Memory operations issued after the ACQUIRE will be completed after the 1800 ACQUIRE operation has completed. 1801 1802 Memory operations issued before the ACQUIRE may be completed after 1803 the ACQUIRE operation has completed. An smp_mb__before_spinlock(), 1804 combined with a following ACQUIRE, orders prior stores against 1805 subsequent loads and stores. Note that this is weaker than smp_mb()! 1806 The smp_mb__before_spinlock() primitive is free on many architectures. 1807 1808 (2) RELEASE operation implication: 1809 1810 Memory operations issued before the RELEASE will be completed before the 1811 RELEASE operation has completed. 1812 1813 Memory operations issued after the RELEASE may be completed before the 1814 RELEASE operation has completed. 1815 1816 (3) ACQUIRE vs ACQUIRE implication: 1817 1818 All ACQUIRE operations issued before another ACQUIRE operation will be 1819 completed before that ACQUIRE operation. 1820 1821 (4) ACQUIRE vs RELEASE implication: 1822 1823 All ACQUIRE operations issued before a RELEASE operation will be 1824 completed before the RELEASE operation. 1825 1826 (5) Failed conditional ACQUIRE implication: 1827 1828 Certain locking variants of the ACQUIRE operation may fail, either due to 1829 being unable to get the lock immediately, or due to receiving an unblocked 1830 signal whilst asleep waiting for the lock to become available. Failed 1831 locks do not imply any sort of barrier. 1832 1833 [!] Note: one of the consequences of lock ACQUIREs and RELEASEs being only 1834 one-way barriers is that the effects of instructions outside of a critical 1835 section may seep into the inside of the critical section. 1836 1837 An ACQUIRE followed by a RELEASE may not be assumed to be full memory barrier 1838 because it is possible for an access preceding the ACQUIRE to happen after the 1839 ACQUIRE, and an access following the RELEASE to happen before the RELEASE, and 1840 the two accesses can themselves then cross: 1841 1842 *A = a; 1843 ACQUIRE M 1844 RELEASE M 1845 *B = b; 1846 1847 may occur as: 1848 1849 ACQUIRE M, STORE *B, STORE *A, RELEASE M 1850 1851 When the ACQUIRE and RELEASE are a lock acquisition and release, 1852 respectively, this same reordering can occur if the lock's ACQUIRE and 1853 RELEASE are to the same lock variable, but only from the perspective of 1854 another CPU not holding that lock. In short, a ACQUIRE followed by an 1855 RELEASE may -not- be assumed to be a full memory barrier. 1856 1857 Similarly, the reverse case of a RELEASE followed by an ACQUIRE does 1858 not imply a full memory barrier. Therefore, the CPU's execution of the 1859 critical sections corresponding to the RELEASE and the ACQUIRE can cross, 1860 so that: 1861 1862 *A = a; 1863 RELEASE M 1864 ACQUIRE N 1865 *B = b; 1866 1867 could occur as: 1868 1869 ACQUIRE N, STORE *B, STORE *A, RELEASE M 1870 1871 It might appear that this reordering could introduce a deadlock. 1872 However, this cannot happen because if such a deadlock threatened, 1873 the RELEASE would simply complete, thereby avoiding the deadlock. 1874 1875 Why does this work? 1876 1877 One key point is that we are only talking about the CPU doing 1878 the reordering, not the compiler. If the compiler (or, for 1879 that matter, the developer) switched the operations, deadlock 1880 -could- occur. 1881 1882 But suppose the CPU reordered the operations. In this case, 1883 the unlock precedes the lock in the assembly code. The CPU 1884 simply elected to try executing the later lock operation first. 1885 If there is a deadlock, this lock operation will simply spin (or 1886 try to sleep, but more on that later). The CPU will eventually 1887 execute the unlock operation (which preceded the lock operation 1888 in the assembly code), which will unravel the potential deadlock, 1889 allowing the lock operation to succeed. 1890 1891 But what if the lock is a sleeplock? In that case, the code will 1892 try to enter the scheduler, where it will eventually encounter 1893 a memory barrier, which will force the earlier unlock operation 1894 to complete, again unraveling the deadlock. There might be 1895 a sleep-unlock race, but the locking primitive needs to resolve 1896 such races properly in any case. 1897 1898 Locks and semaphores may not provide any guarantee of ordering on UP compiled 1899 systems, and so cannot be counted on in such a situation to actually achieve 1900 anything at all - especially with respect to I/O accesses - unless combined 1901 with interrupt disabling operations. 1902 1903 See also the section on "Inter-CPU locking barrier effects". 1904 1905 1906 As an example, consider the following: 1907 1908 *A = a; 1909 *B = b; 1910 ACQUIRE 1911 *C = c; 1912 *D = d; 1913 RELEASE 1914 *E = e; 1915 *F = f; 1916 1917 The following sequence of events is acceptable: 1918 1919 ACQUIRE, {*F,*A}, *E, {*C,*D}, *B, RELEASE 1920 1921 [+] Note that {*F,*A} indicates a combined access. 1922 1923 But none of the following are: 1924 1925 {*F,*A}, *B, ACQUIRE, *C, *D, RELEASE, *E 1926 *A, *B, *C, ACQUIRE, *D, RELEASE, *E, *F 1927 *A, *B, ACQUIRE, *C, RELEASE, *D, *E, *F 1928 *B, ACQUIRE, *C, *D, RELEASE, {*F,*A}, *E 1929 1930 1931 1932 INTERRUPT DISABLING FUNCTIONS 1933 ----------------------------- 1934 1935 Functions that disable interrupts (ACQUIRE equivalent) and enable interrupts 1936 (RELEASE equivalent) will act as compiler barriers only. So if memory or I/O 1937 barriers are required in such a situation, they must be provided from some 1938 other means. 1939 1940 1941 SLEEP AND WAKE-UP FUNCTIONS 1942 --------------------------- 1943 1944 Sleeping and waking on an event flagged in global data can be viewed as an 1945 interaction between two pieces of data: the task state of the task waiting for 1946 the event and the global data used to indicate the event. To make sure that 1947 these appear to happen in the right order, the primitives to begin the process 1948 of going to sleep, and the primitives to initiate a wake up imply certain 1949 barriers. 1950 1951 Firstly, the sleeper normally follows something like this sequence of events: 1952 1953 for (;;) { 1954 set_current_state(TASK_UNINTERRUPTIBLE); 1955 if (event_indicated) 1956 break; 1957 schedule(); 1958 } 1959 1960 A general memory barrier is interpolated automatically by set_current_state() 1961 after it has altered the task state: 1962 1963 CPU 1 1964 =============================== 1965 set_current_state(); 1966 smp_store_mb(); 1967 STORE current->state 1968 <general barrier> 1969 LOAD event_indicated 1970 1971 set_current_state() may be wrapped by: 1972 1973 prepare_to_wait(); 1974 prepare_to_wait_exclusive(); 1975 1976 which therefore also imply a general memory barrier after setting the state. 1977 The whole sequence above is available in various canned forms, all of which 1978 interpolate the memory barrier in the right place: 1979 1980 wait_event(); 1981 wait_event_interruptible(); 1982 wait_event_interruptible_exclusive(); 1983 wait_event_interruptible_timeout(); 1984 wait_event_killable(); 1985 wait_event_timeout(); 1986 wait_on_bit(); 1987 wait_on_bit_lock(); 1988 1989 1990 Secondly, code that performs a wake up normally follows something like this: 1991 1992 event_indicated = 1; 1993 wake_up(&event_wait_queue); 1994 1995 or: 1996 1997 event_indicated = 1; 1998 wake_up_process(event_daemon); 1999 2000 A write memory barrier is implied by wake_up() and co. if and only if they wake 2001 something up. The barrier occurs before the task state is cleared, and so sits 2002 between the STORE to indicate the event and the STORE to set TASK_RUNNING: 2003 2004 CPU 1 CPU 2 2005 =============================== =============================== 2006 set_current_state(); STORE event_indicated 2007 smp_store_mb(); wake_up(); 2008 STORE current->state <write barrier> 2009 <general barrier> STORE current->state 2010 LOAD event_indicated 2011 2012 To repeat, this write memory barrier is present if and only if something 2013 is actually awakened. To see this, consider the following sequence of 2014 events, where X and Y are both initially zero: 2015 2016 CPU 1 CPU 2 2017 =============================== =============================== 2018 X = 1; STORE event_indicated 2019 smp_mb(); wake_up(); 2020 Y = 1; wait_event(wq, Y == 1); 2021 wake_up(); load from Y sees 1, no memory barrier 2022 load from X might see 0 2023 2024 In contrast, if a wakeup does occur, CPU 2's load from X would be guaranteed 2025 to see 1. 2026 2027 The available waker functions include: 2028 2029 complete(); 2030 wake_up(); 2031 wake_up_all(); 2032 wake_up_bit(); 2033 wake_up_interruptible(); 2034 wake_up_interruptible_all(); 2035 wake_up_interruptible_nr(); 2036 wake_up_interruptible_poll(); 2037 wake_up_interruptible_sync(); 2038 wake_up_interruptible_sync_poll(); 2039 wake_up_locked(); 2040 wake_up_locked_poll(); 2041 wake_up_nr(); 2042 wake_up_poll(); 2043 wake_up_process(); 2044 2045 2046 [!] Note that the memory barriers implied by the sleeper and the waker do _not_ 2047 order multiple stores before the wake-up with respect to loads of those stored 2048 values after the sleeper has called set_current_state(). For instance, if the 2049 sleeper does: 2050 2051 set_current_state(TASK_INTERRUPTIBLE); 2052 if (event_indicated) 2053 break; 2054 __set_current_state(TASK_RUNNING); 2055 do_something(my_data); 2056 2057 and the waker does: 2058 2059 my_data = value; 2060 event_indicated = 1; 2061 wake_up(&event_wait_queue); 2062 2063 there's no guarantee that the change to event_indicated will be perceived by 2064 the sleeper as coming after the change to my_data. In such a circumstance, the 2065 code on both sides must interpolate its own memory barriers between the 2066 separate data accesses. Thus the above sleeper ought to do: 2067 2068 set_current_state(TASK_INTERRUPTIBLE); 2069 if (event_indicated) { 2070 smp_rmb(); 2071 do_something(my_data); 2072 } 2073 2074 and the waker should do: 2075 2076 my_data = value; 2077 smp_wmb(); 2078 event_indicated = 1; 2079 wake_up(&event_wait_queue); 2080 2081 2082 MISCELLANEOUS FUNCTIONS 2083 ----------------------- 2084 2085 Other functions that imply barriers: 2086 2087 (*) schedule() and similar imply full memory barriers. 2088 2089 2090 =================================== 2091 INTER-CPU ACQUIRING BARRIER EFFECTS 2092 =================================== 2093 2094 On SMP systems locking primitives give a more substantial form of barrier: one 2095 that does affect memory access ordering on other CPUs, within the context of 2096 conflict on any particular lock. 2097 2098 2099 ACQUIRES VS MEMORY ACCESSES 2100 --------------------------- 2101 2102 Consider the following: the system has a pair of spinlocks (M) and (Q), and 2103 three CPUs; then should the following sequence of events occur: 2104 2105 CPU 1 CPU 2 2106 =============================== =============================== 2107 WRITE_ONCE(*A, a); WRITE_ONCE(*E, e); 2108 ACQUIRE M ACQUIRE Q 2109 WRITE_ONCE(*B, b); WRITE_ONCE(*F, f); 2110 WRITE_ONCE(*C, c); WRITE_ONCE(*G, g); 2111 RELEASE M RELEASE Q 2112 WRITE_ONCE(*D, d); WRITE_ONCE(*H, h); 2113 2114 Then there is no guarantee as to what order CPU 3 will see the accesses to *A 2115 through *H occur in, other than the constraints imposed by the separate locks 2116 on the separate CPUs. It might, for example, see: 2117 2118 *E, ACQUIRE M, ACQUIRE Q, *G, *C, *F, *A, *B, RELEASE Q, *D, *H, RELEASE M 2119 2120 But it won't see any of: 2121 2122 *B, *C or *D preceding ACQUIRE M 2123 *A, *B or *C following RELEASE M 2124 *F, *G or *H preceding ACQUIRE Q 2125 *E, *F or *G following RELEASE Q 2126 2127 2128 2129 ACQUIRES VS I/O ACCESSES 2130 ------------------------ 2131 2132 Under certain circumstances (especially involving NUMA), I/O accesses within 2133 two spinlocked sections on two different CPUs may be seen as interleaved by the 2134 PCI bridge, because the PCI bridge does not necessarily participate in the 2135 cache-coherence protocol, and is therefore incapable of issuing the required 2136 read memory barriers. 2137 2138 For example: 2139 2140 CPU 1 CPU 2 2141 =============================== =============================== 2142 spin_lock(Q) 2143 writel(0, ADDR) 2144 writel(1, DATA); 2145 spin_unlock(Q); 2146 spin_lock(Q); 2147 writel(4, ADDR); 2148 writel(5, DATA); 2149 spin_unlock(Q); 2150 2151 may be seen by the PCI bridge as follows: 2152 2153 STORE *ADDR = 0, STORE *ADDR = 4, STORE *DATA = 1, STORE *DATA = 5 2154 2155 which would probably cause the hardware to malfunction. 2156 2157 2158 What is necessary here is to intervene with an mmiowb() before dropping the 2159 spinlock, for example: 2160 2161 CPU 1 CPU 2 2162 =============================== =============================== 2163 spin_lock(Q) 2164 writel(0, ADDR) 2165 writel(1, DATA); 2166 mmiowb(); 2167 spin_unlock(Q); 2168 spin_lock(Q); 2169 writel(4, ADDR); 2170 writel(5, DATA); 2171 mmiowb(); 2172 spin_unlock(Q); 2173 2174 this will ensure that the two stores issued on CPU 1 appear at the PCI bridge 2175 before either of the stores issued on CPU 2. 2176 2177 2178 Furthermore, following a store by a load from the same device obviates the need 2179 for the mmiowb(), because the load forces the store to complete before the load 2180 is performed: 2181 2182 CPU 1 CPU 2 2183 =============================== =============================== 2184 spin_lock(Q) 2185 writel(0, ADDR) 2186 a = readl(DATA); 2187 spin_unlock(Q); 2188 spin_lock(Q); 2189 writel(4, ADDR); 2190 b = readl(DATA); 2191 spin_unlock(Q); 2192 2193 2194 See Documentation/DocBook/deviceiobook.tmpl for more information. 2195 2196 2197 ================================= 2198 WHERE ARE MEMORY BARRIERS NEEDED? 2199 ================================= 2200 2201 Under normal operation, memory operation reordering is generally not going to 2202 be a problem as a single-threaded linear piece of code will still appear to 2203 work correctly, even if it's in an SMP kernel. There are, however, four 2204 circumstances in which reordering definitely _could_ be a problem: 2205 2206 (*) Interprocessor interaction. 2207 2208 (*) Atomic operations. 2209 2210 (*) Accessing devices. 2211 2212 (*) Interrupts. 2213 2214 2215 INTERPROCESSOR INTERACTION 2216 -------------------------- 2217 2218 When there's a system with more than one processor, more than one CPU in the 2219 system may be working on the same data set at the same time. This can cause 2220 synchronisation problems, and the usual way of dealing with them is to use 2221 locks. Locks, however, are quite expensive, and so it may be preferable to 2222 operate without the use of a lock if at all possible. In such a case 2223 operations that affect both CPUs may have to be carefully ordered to prevent 2224 a malfunction. 2225 2226 Consider, for example, the R/W semaphore slow path. Here a waiting process is 2227 queued on the semaphore, by virtue of it having a piece of its stack linked to 2228 the semaphore's list of waiting processes: 2229 2230 struct rw_semaphore { 2231 ... 2232 spinlock_t lock; 2233 struct list_head waiters; 2234 }; 2235 2236 struct rwsem_waiter { 2237 struct list_head list; 2238 struct task_struct *task; 2239 }; 2240 2241 To wake up a particular waiter, the up_read() or up_write() functions have to: 2242 2243 (1) read the next pointer from this waiter's record to know as to where the 2244 next waiter record is; 2245 2246 (2) read the pointer to the waiter's task structure; 2247 2248 (3) clear the task pointer to tell the waiter it has been given the semaphore; 2249 2250 (4) call wake_up_process() on the task; and 2251 2252 (5) release the reference held on the waiter's task struct. 2253 2254 In other words, it has to perform this sequence of events: 2255 2256 LOAD waiter->list.next; 2257 LOAD waiter->task; 2258 STORE waiter->task; 2259 CALL wakeup 2260 RELEASE task 2261 2262 and if any of these steps occur out of order, then the whole thing may 2263 malfunction. 2264 2265 Once it has queued itself and dropped the semaphore lock, the waiter does not 2266 get the lock again; it instead just waits for its task pointer to be cleared 2267 before proceeding. Since the record is on the waiter's stack, this means that 2268 if the task pointer is cleared _before_ the next pointer in the list is read, 2269 another CPU might start processing the waiter and might clobber the waiter's 2270 stack before the up*() function has a chance to read the next pointer. 2271 2272 Consider then what might happen to the above sequence of events: 2273 2274 CPU 1 CPU 2 2275 =============================== =============================== 2276 down_xxx() 2277 Queue waiter 2278 Sleep 2279 up_yyy() 2280 LOAD waiter->task; 2281 STORE waiter->task; 2282 Woken up by other event 2283 <preempt> 2284 Resume processing 2285 down_xxx() returns 2286 call foo() 2287 foo() clobbers *waiter 2288 </preempt> 2289 LOAD waiter->list.next; 2290 --- OOPS --- 2291 2292 This could be dealt with using the semaphore lock, but then the down_xxx() 2293 function has to needlessly get the spinlock again after being woken up. 2294 2295 The way to deal with this is to insert a general SMP memory barrier: 2296 2297 LOAD waiter->list.next; 2298 LOAD waiter->task; 2299 smp_mb(); 2300 STORE waiter->task; 2301 CALL wakeup 2302 RELEASE task 2303 2304 In this case, the barrier makes a guarantee that all memory accesses before the 2305 barrier will appear to happen before all the memory accesses after the barrier 2306 with respect to the other CPUs on the system. It does _not_ guarantee that all 2307 the memory accesses before the barrier will be complete by the time the barrier 2308 instruction itself is complete. 2309 2310 On a UP system - where this wouldn't be a problem - the smp_mb() is just a 2311 compiler barrier, thus making sure the compiler emits the instructions in the 2312 right order without actually intervening in the CPU. Since there's only one 2313 CPU, that CPU's dependency ordering logic will take care of everything else. 2314 2315 2316 ATOMIC OPERATIONS 2317 ----------------- 2318 2319 Whilst they are technically interprocessor interaction considerations, atomic 2320 operations are noted specially as some of them imply full memory barriers and 2321 some don't, but they're very heavily relied on as a group throughout the 2322 kernel. 2323 2324 Any atomic operation that modifies some state in memory and returns information 2325 about the state (old or new) implies an SMP-conditional general memory barrier 2326 (smp_mb()) on each side of the actual operation (with the exception of 2327 explicit lock operations, described later). These include: 2328 2329 xchg(); 2330 atomic_xchg(); atomic_long_xchg(); 2331 atomic_inc_return(); atomic_long_inc_return(); 2332 atomic_dec_return(); atomic_long_dec_return(); 2333 atomic_add_return(); atomic_long_add_return(); 2334 atomic_sub_return(); atomic_long_sub_return(); 2335 atomic_inc_and_test(); atomic_long_inc_and_test(); 2336 atomic_dec_and_test(); atomic_long_dec_and_test(); 2337 atomic_sub_and_test(); atomic_long_sub_and_test(); 2338 atomic_add_negative(); atomic_long_add_negative(); 2339 test_and_set_bit(); 2340 test_and_clear_bit(); 2341 test_and_change_bit(); 2342 2343 /* when succeeds */ 2344 cmpxchg(); 2345 atomic_cmpxchg(); atomic_long_cmpxchg(); 2346 atomic_add_unless(); atomic_long_add_unless(); 2347 2348 These are used for such things as implementing ACQUIRE-class and RELEASE-class 2349 operations and adjusting reference counters towards object destruction, and as 2350 such the implicit memory barrier effects are necessary. 2351 2352 2353 The following operations are potential problems as they do _not_ imply memory 2354 barriers, but might be used for implementing such things as RELEASE-class 2355 operations: 2356 2357 atomic_set(); 2358 set_bit(); 2359 clear_bit(); 2360 change_bit(); 2361 2362 With these the appropriate explicit memory barrier should be used if necessary 2363 (smp_mb__before_atomic() for instance). 2364 2365 2366 The following also do _not_ imply memory barriers, and so may require explicit 2367 memory barriers under some circumstances (smp_mb__before_atomic() for 2368 instance): 2369 2370 atomic_add(); 2371 atomic_sub(); 2372 atomic_inc(); 2373 atomic_dec(); 2374 2375 If they're used for statistics generation, then they probably don't need memory 2376 barriers, unless there's a coupling between statistical data. 2377 2378 If they're used for reference counting on an object to control its lifetime, 2379 they probably don't need memory barriers because either the reference count 2380 will be adjusted inside a locked section, or the caller will already hold 2381 sufficient references to make the lock, and thus a memory barrier unnecessary. 2382 2383 If they're used for constructing a lock of some description, then they probably 2384 do need memory barriers as a lock primitive generally has to do things in a 2385 specific order. 2386 2387 Basically, each usage case has to be carefully considered as to whether memory 2388 barriers are needed or not. 2389 2390 The following operations are special locking primitives: 2391 2392 test_and_set_bit_lock(); 2393 clear_bit_unlock(); 2394 __clear_bit_unlock(); 2395 2396 These implement ACQUIRE-class and RELEASE-class operations. These should be used in 2397 preference to other operations when implementing locking primitives, because 2398 their implementations can be optimised on many architectures. 2399 2400 [!] Note that special memory barrier primitives are available for these 2401 situations because on some CPUs the atomic instructions used imply full memory 2402 barriers, and so barrier instructions are superfluous in conjunction with them, 2403 and in such cases the special barrier primitives will be no-ops. 2404 2405 See Documentation/atomic_ops.txt for more information. 2406 2407 2408 ACCESSING DEVICES 2409 ----------------- 2410 2411 Many devices can be memory mapped, and so appear to the CPU as if they're just 2412 a set of memory locations. To control such a device, the driver usually has to 2413 make the right memory accesses in exactly the right order. 2414 2415 However, having a clever CPU or a clever compiler creates a potential problem 2416 in that the carefully sequenced accesses in the driver code won't reach the 2417 device in the requisite order if the CPU or the compiler thinks it is more 2418 efficient to reorder, combine or merge accesses - something that would cause 2419 the device to malfunction. 2420 2421 Inside of the Linux kernel, I/O should be done through the appropriate accessor 2422 routines - such as inb() or writel() - which know how to make such accesses 2423 appropriately sequential. Whilst this, for the most part, renders the explicit 2424 use of memory barriers unnecessary, there are a couple of situations where they 2425 might be needed: 2426 2427 (1) On some systems, I/O stores are not strongly ordered across all CPUs, and 2428 so for _all_ general drivers locks should be used and mmiowb() must be 2429 issued prior to unlocking the critical section. 2430 2431 (2) If the accessor functions are used to refer to an I/O memory window with 2432 relaxed memory access properties, then _mandatory_ memory barriers are 2433 required to enforce ordering. 2434 2435 See Documentation/DocBook/deviceiobook.tmpl for more information. 2436 2437 2438 INTERRUPTS 2439 ---------- 2440 2441 A driver may be interrupted by its own interrupt service routine, and thus the 2442 two parts of the driver may interfere with each other's attempts to control or 2443 access the device. 2444 2445 This may be alleviated - at least in part - by disabling local interrupts (a 2446 form of locking), such that the critical operations are all contained within 2447 the interrupt-disabled section in the driver. Whilst the driver's interrupt 2448 routine is executing, the driver's core may not run on the same CPU, and its 2449 interrupt is not permitted to happen again until the current interrupt has been 2450 handled, thus the interrupt handler does not need to lock against that. 2451 2452 However, consider a driver that was talking to an ethernet card that sports an 2453 address register and a data register. If that driver's core talks to the card 2454 under interrupt-disablement and then the driver's interrupt handler is invoked: 2455 2456 LOCAL IRQ DISABLE 2457 writew(ADDR, 3); 2458 writew(DATA, y); 2459 LOCAL IRQ ENABLE 2460 <interrupt> 2461 writew(ADDR, 4); 2462 q = readw(DATA); 2463 </interrupt> 2464 2465 The store to the data register might happen after the second store to the 2466 address register if ordering rules are sufficiently relaxed: 2467 2468 STORE *ADDR = 3, STORE *ADDR = 4, STORE *DATA = y, q = LOAD *DATA 2469 2470 2471 If ordering rules are relaxed, it must be assumed that accesses done inside an 2472 interrupt disabled section may leak outside of it and may interleave with 2473 accesses performed in an interrupt - and vice versa - unless implicit or 2474 explicit barriers are used. 2475 2476 Normally this won't be a problem because the I/O accesses done inside such 2477 sections will include synchronous load operations on strictly ordered I/O 2478 registers that form implicit I/O barriers. If this isn't sufficient then an 2479 mmiowb() may need to be used explicitly. 2480 2481 2482 A similar situation may occur between an interrupt routine and two routines 2483 running on separate CPUs that communicate with each other. If such a case is 2484 likely, then interrupt-disabling locks should be used to guarantee ordering. 2485 2486 2487 ========================== 2488 KERNEL I/O BARRIER EFFECTS 2489 ========================== 2490 2491 When accessing I/O memory, drivers should use the appropriate accessor 2492 functions: 2493 2494 (*) inX(), outX(): 2495 2496 These are intended to talk to I/O space rather than memory space, but 2497 that's primarily a CPU-specific concept. The i386 and x86_64 processors do 2498 indeed have special I/O space access cycles and instructions, but many 2499 CPUs don't have such a concept. 2500 2501 The PCI bus, amongst others, defines an I/O space concept which - on such 2502 CPUs as i386 and x86_64 - readily maps to the CPU's concept of I/O 2503 space. However, it may also be mapped as a virtual I/O space in the CPU's 2504 memory map, particularly on those CPUs that don't support alternate I/O 2505 spaces. 2506 2507 Accesses to this space may be fully synchronous (as on i386), but 2508 intermediary bridges (such as the PCI host bridge) may not fully honour 2509 that. 2510 2511 They are guaranteed to be fully ordered with respect to each other. 2512 2513 They are not guaranteed to be fully ordered with respect to other types of 2514 memory and I/O operation. 2515 2516 (*) readX(), writeX(): 2517 2518 Whether these are guaranteed to be fully ordered and uncombined with 2519 respect to each other on the issuing CPU depends on the characteristics 2520 defined for the memory window through which they're accessing. On later 2521 i386 architecture machines, for example, this is controlled by way of the 2522 MTRR registers. 2523 2524 Ordinarily, these will be guaranteed to be fully ordered and uncombined, 2525 provided they're not accessing a prefetchable device. 2526 2527 However, intermediary hardware (such as a PCI bridge) may indulge in 2528 deferral if it so wishes; to flush a store, a load from the same location 2529 is preferred[*], but a load from the same device or from configuration 2530 space should suffice for PCI. 2531 2532 [*] NOTE! attempting to load from the same location as was written to may 2533 cause a malfunction - consider the 16550 Rx/Tx serial registers for 2534 example. 2535 2536 Used with prefetchable I/O memory, an mmiowb() barrier may be required to 2537 force stores to be ordered. 2538 2539 Please refer to the PCI specification for more information on interactions 2540 between PCI transactions. 2541 2542 (*) readX_relaxed(), writeX_relaxed() 2543 2544 These are similar to readX() and writeX(), but provide weaker memory 2545 ordering guarantees. Specifically, they do not guarantee ordering with 2546 respect to normal memory accesses (e.g. DMA buffers) nor do they guarantee 2547 ordering with respect to LOCK or UNLOCK operations. If the latter is 2548 required, an mmiowb() barrier can be used. Note that relaxed accesses to 2549 the same peripheral are guaranteed to be ordered with respect to each 2550 other. 2551 2552 (*) ioreadX(), iowriteX() 2553 2554 These will perform appropriately for the type of access they're actually 2555 doing, be it inX()/outX() or readX()/writeX(). 2556 2557 2558 ======================================== 2559 ASSUMED MINIMUM EXECUTION ORDERING MODEL 2560 ======================================== 2561 2562 It has to be assumed that the conceptual CPU is weakly-ordered but that it will 2563 maintain the appearance of program causality with respect to itself. Some CPUs 2564 (such as i386 or x86_64) are more constrained than others (such as powerpc or 2565 frv), and so the most relaxed case (namely DEC Alpha) must be assumed outside 2566 of arch-specific code. 2567 2568 This means that it must be considered that the CPU will execute its instruction 2569 stream in any order it feels like - or even in parallel - provided that if an 2570 instruction in the stream depends on an earlier instruction, then that 2571 earlier instruction must be sufficiently complete[*] before the later 2572 instruction may proceed; in other words: provided that the appearance of 2573 causality is maintained. 2574 2575 [*] Some instructions have more than one effect - such as changing the 2576 condition codes, changing registers or changing memory - and different 2577 instructions may depend on different effects. 2578 2579 A CPU may also discard any instruction sequence that winds up having no 2580 ultimate effect. For example, if two adjacent instructions both load an 2581 immediate value into the same register, the first may be discarded. 2582 2583 2584 Similarly, it has to be assumed that compiler might reorder the instruction 2585 stream in any way it sees fit, again provided the appearance of causality is 2586 maintained. 2587 2588 2589 ============================ 2590 THE EFFECTS OF THE CPU CACHE 2591 ============================ 2592 2593 The way cached memory operations are perceived across the system is affected to 2594 a certain extent by the caches that lie between CPUs and memory, and by the 2595 memory coherence system that maintains the consistency of state in the system. 2596 2597 As far as the way a CPU interacts with another part of the system through the 2598 caches goes, the memory system has to include the CPU's caches, and memory 2599 barriers for the most part act at the interface between the CPU and its cache 2600 (memory barriers logically act on the dotted line in the following diagram): 2601 2602 <--- CPU ---> : <----------- Memory -----------> 2603 : 2604 +--------+ +--------+ : +--------+ +-----------+ 2605 | | | | : | | | | +--------+ 2606 | CPU | | Memory | : | CPU | | | | | 2607 | Core |--->| Access |----->| Cache |<-->| | | | 2608 | | | Queue | : | | | |--->| Memory | 2609 | | | | : | | | | | | 2610 +--------+ +--------+ : +--------+ | | | | 2611 : | Cache | +--------+ 2612 : | Coherency | 2613 : | Mechanism | +--------+ 2614 +--------+ +--------+ : +--------+ | | | | 2615 | | | | : | | | | | | 2616 | CPU | | Memory | : | CPU | | |--->| Device | 2617 | Core |--->| Access |----->| Cache |<-->| | | | 2618 | | | Queue | : | | | | | | 2619 | | | | : | | | | +--------+ 2620 +--------+ +--------+ : +--------+ +-----------+ 2621 : 2622 : 2623 2624 Although any particular load or store may not actually appear outside of the 2625 CPU that issued it since it may have been satisfied within the CPU's own cache, 2626 it will still appear as if the full memory access had taken place as far as the 2627 other CPUs are concerned since the cache coherency mechanisms will migrate the 2628 cacheline over to the accessing CPU and propagate the effects upon conflict. 2629 2630 The CPU core may execute instructions in any order it deems fit, provided the 2631 expected program causality appears to be maintained. Some of the instructions 2632 generate load and store operations which then go into the queue of memory 2633 accesses to be performed. The core may place these in the queue in any order 2634 it wishes, and continue execution until it is forced to wait for an instruction 2635 to complete. 2636 2637 What memory barriers are concerned with is controlling the order in which 2638 accesses cross from the CPU side of things to the memory side of things, and 2639 the order in which the effects are perceived to happen by the other observers 2640 in the system. 2641 2642 [!] Memory barriers are _not_ needed within a given CPU, as CPUs always see 2643 their own loads and stores as if they had happened in program order. 2644 2645 [!] MMIO or other device accesses may bypass the cache system. This depends on 2646 the properties of the memory window through which devices are accessed and/or 2647 the use of any special device communication instructions the CPU may have. 2648 2649 2650 CACHE COHERENCY 2651 --------------- 2652 2653 Life isn't quite as simple as it may appear above, however: for while the 2654 caches are expected to be coherent, there's no guarantee that that coherency 2655 will be ordered. This means that whilst changes made on one CPU will 2656 eventually become visible on all CPUs, there's no guarantee that they will 2657 become apparent in the same order on those other CPUs. 2658 2659 2660 Consider dealing with a system that has a pair of CPUs (1 & 2), each of which 2661 has a pair of parallel data caches (CPU 1 has A/B, and CPU 2 has C/D): 2662 2663 : 2664 : +--------+ 2665 : +---------+ | | 2666 +--------+ : +--->| Cache A |<------->| | 2667 | | : | +---------+ | | 2668 | CPU 1 |<---+ | | 2669 | | : | +---------+ | | 2670 +--------+ : +--->| Cache B |<------->| | 2671 : +---------+ | | 2672 : | Memory | 2673 : +---------+ | System | 2674 +--------+ : +--->| Cache C |<------->| | 2675 | | : | +---------+ | | 2676 | CPU 2 |<---+ | | 2677 | | : | +---------+ | | 2678 +--------+ : +--->| Cache D |<------->| | 2679 : +---------+ | | 2680 : +--------+ 2681 : 2682 2683 Imagine the system has the following properties: 2684 2685 (*) an odd-numbered cache line may be in cache A, cache C or it may still be 2686 resident in memory; 2687 2688 (*) an even-numbered cache line may be in cache B, cache D or it may still be 2689 resident in memory; 2690 2691 (*) whilst the CPU core is interrogating one cache, the other cache may be 2692 making use of the bus to access the rest of the system - perhaps to 2693 displace a dirty cacheline or to do a speculative load; 2694 2695 (*) each cache has a queue of operations that need to be applied to that cache 2696 to maintain coherency with the rest of the system; 2697 2698 (*) the coherency queue is not flushed by normal loads to lines already 2699 present in the cache, even though the contents of the queue may 2700 potentially affect those loads. 2701 2702 Imagine, then, that two writes are made on the first CPU, with a write barrier 2703 between them to guarantee that they will appear to reach that CPU's caches in 2704 the requisite order: 2705 2706 CPU 1 CPU 2 COMMENT 2707 =============== =============== ======================================= 2708 u == 0, v == 1 and p == &u, q == &u 2709 v = 2; 2710 smp_wmb(); Make sure change to v is visible before 2711 change to p 2712 <A:modify v=2> v is now in cache A exclusively 2713 p = &v; 2714 <B:modify p=&v> p is now in cache B exclusively 2715 2716 The write memory barrier forces the other CPUs in the system to perceive that 2717 the local CPU's caches have apparently been updated in the correct order. But 2718 now imagine that the second CPU wants to read those values: 2719 2720 CPU 1 CPU 2 COMMENT 2721 =============== =============== ======================================= 2722 ... 2723 q = p; 2724 x = *q; 2725 2726 The above pair of reads may then fail to happen in the expected order, as the 2727 cacheline holding p may get updated in one of the second CPU's caches whilst 2728 the update to the cacheline holding v is delayed in the other of the second 2729 CPU's caches by some other cache event: 2730 2731 CPU 1 CPU 2 COMMENT 2732 =============== =============== ======================================= 2733 u == 0, v == 1 and p == &u, q == &u 2734 v = 2; 2735 smp_wmb(); 2736 <A:modify v=2> <C:busy> 2737 <C:queue v=2> 2738 p = &v; q = p; 2739 <D:request p> 2740 <B:modify p=&v> <D:commit p=&v> 2741 <D:read p> 2742 x = *q; 2743 <C:read *q> Reads from v before v updated in cache 2744 <C:unbusy> 2745 <C:commit v=2> 2746 2747 Basically, whilst both cachelines will be updated on CPU 2 eventually, there's 2748 no guarantee that, without intervention, the order of update will be the same 2749 as that committed on CPU 1. 2750 2751 2752 To intervene, we need to interpolate a data dependency barrier or a read 2753 barrier between the loads. This will force the cache to commit its coherency 2754 queue before processing any further requests: 2755 2756 CPU 1 CPU 2 COMMENT 2757 =============== =============== ======================================= 2758 u == 0, v == 1 and p == &u, q == &u 2759 v = 2; 2760 smp_wmb(); 2761 <A:modify v=2> <C:busy> 2762 <C:queue v=2> 2763 p = &v; q = p; 2764 <D:request p> 2765 <B:modify p=&v> <D:commit p=&v> 2766 <D:read p> 2767 smp_read_barrier_depends() 2768 <C:unbusy> 2769 <C:commit v=2> 2770 x = *q; 2771 <C:read *q> Reads from v after v updated in cache 2772 2773 2774 This sort of problem can be encountered on DEC Alpha processors as they have a 2775 split cache that improves performance by making better use of the data bus. 2776 Whilst most CPUs do imply a data dependency barrier on the read when a memory 2777 access depends on a read, not all do, so it may not be relied on. 2778 2779 Other CPUs may also have split caches, but must coordinate between the various 2780 cachelets for normal memory accesses. The semantics of the Alpha removes the 2781 need for coordination in the absence of memory barriers. 2782 2783 2784 CACHE COHERENCY VS DMA 2785 ---------------------- 2786 2787 Not all systems maintain cache coherency with respect to devices doing DMA. In 2788 such cases, a device attempting DMA may obtain stale data from RAM because 2789 dirty cache lines may be resident in the caches of various CPUs, and may not 2790 have been written back to RAM yet. To deal with this, the appropriate part of 2791 the kernel must flush the overlapping bits of cache on each CPU (and maybe 2792 invalidate them as well). 2793 2794 In addition, the data DMA'd to RAM by a device may be overwritten by dirty 2795 cache lines being written back to RAM from a CPU's cache after the device has 2796 installed its own data, or cache lines present in the CPU's cache may simply 2797 obscure the fact that RAM has been updated, until at such time as the cacheline 2798 is discarded from the CPU's cache and reloaded. To deal with this, the 2799 appropriate part of the kernel must invalidate the overlapping bits of the 2800 cache on each CPU. 2801 2802 See Documentation/cachetlb.txt for more information on cache management. 2803 2804 2805 CACHE COHERENCY VS MMIO 2806 ----------------------- 2807 2808 Memory mapped I/O usually takes place through memory locations that are part of 2809 a window in the CPU's memory space that has different properties assigned than 2810 the usual RAM directed window. 2811 2812 Amongst these properties is usually the fact that such accesses bypass the 2813 caching entirely and go directly to the device buses. This means MMIO accesses 2814 may, in effect, overtake accesses to cached memory that were emitted earlier. 2815 A memory barrier isn't sufficient in such a case, but rather the cache must be 2816 flushed between the cached memory write and the MMIO access if the two are in 2817 any way dependent. 2818 2819 2820 ========================= 2821 THE THINGS CPUS GET UP TO 2822 ========================= 2823 2824 A programmer might take it for granted that the CPU will perform memory 2825 operations in exactly the order specified, so that if the CPU is, for example, 2826 given the following piece of code to execute: 2827 2828 a = READ_ONCE(*A); 2829 WRITE_ONCE(*B, b); 2830 c = READ_ONCE(*C); 2831 d = READ_ONCE(*D); 2832 WRITE_ONCE(*E, e); 2833 2834 they would then expect that the CPU will complete the memory operation for each 2835 instruction before moving on to the next one, leading to a definite sequence of 2836 operations as seen by external observers in the system: 2837 2838 LOAD *A, STORE *B, LOAD *C, LOAD *D, STORE *E. 2839 2840 2841 Reality is, of course, much messier. With many CPUs and compilers, the above 2842 assumption doesn't hold because: 2843 2844 (*) loads are more likely to need to be completed immediately to permit 2845 execution progress, whereas stores can often be deferred without a 2846 problem; 2847 2848 (*) loads may be done speculatively, and the result discarded should it prove 2849 to have been unnecessary; 2850 2851 (*) loads may be done speculatively, leading to the result having been fetched 2852 at the wrong time in the expected sequence of events; 2853 2854 (*) the order of the memory accesses may be rearranged to promote better use 2855 of the CPU buses and caches; 2856 2857 (*) loads and stores may be combined to improve performance when talking to 2858 memory or I/O hardware that can do batched accesses of adjacent locations, 2859 thus cutting down on transaction setup costs (memory and PCI devices may 2860 both be able to do this); and 2861 2862 (*) the CPU's data cache may affect the ordering, and whilst cache-coherency 2863 mechanisms may alleviate this - once the store has actually hit the cache 2864 - there's no guarantee that the coherency management will be propagated in 2865 order to other CPUs. 2866 2867 So what another CPU, say, might actually observe from the above piece of code 2868 is: 2869 2870 LOAD *A, ..., LOAD {*C,*D}, STORE *E, STORE *B 2871 2872 (Where "LOAD {*C,*D}" is a combined load) 2873 2874 2875 However, it is guaranteed that a CPU will be self-consistent: it will see its 2876 _own_ accesses appear to be correctly ordered, without the need for a memory 2877 barrier. For instance with the following code: 2878 2879 U = READ_ONCE(*A); 2880 WRITE_ONCE(*A, V); 2881 WRITE_ONCE(*A, W); 2882 X = READ_ONCE(*A); 2883 WRITE_ONCE(*A, Y); 2884 Z = READ_ONCE(*A); 2885 2886 and assuming no intervention by an external influence, it can be assumed that 2887 the final result will appear to be: 2888 2889 U == the original value of *A 2890 X == W 2891 Z == Y 2892 *A == Y 2893 2894 The code above may cause the CPU to generate the full sequence of memory 2895 accesses: 2896 2897 U=LOAD *A, STORE *A=V, STORE *A=W, X=LOAD *A, STORE *A=Y, Z=LOAD *A 2898 2899 in that order, but, without intervention, the sequence may have almost any 2900 combination of elements combined or discarded, provided the program's view 2901 of the world remains consistent. Note that READ_ONCE() and WRITE_ONCE() 2902 are -not- optional in the above example, as there are architectures 2903 where a given CPU might reorder successive loads to the same location. 2904 On such architectures, READ_ONCE() and WRITE_ONCE() do whatever is 2905 necessary to prevent this, for example, on Itanium the volatile casts 2906 used by READ_ONCE() and WRITE_ONCE() cause GCC to emit the special ld.acq 2907 and st.rel instructions (respectively) that prevent such reordering. 2908 2909 The compiler may also combine, discard or defer elements of the sequence before 2910 the CPU even sees them. 2911 2912 For instance: 2913 2914 *A = V; 2915 *A = W; 2916 2917 may be reduced to: 2918 2919 *A = W; 2920 2921 since, without either a write barrier or an WRITE_ONCE(), it can be 2922 assumed that the effect of the storage of V to *A is lost. Similarly: 2923 2924 *A = Y; 2925 Z = *A; 2926 2927 may, without a memory barrier or an READ_ONCE() and WRITE_ONCE(), be 2928 reduced to: 2929 2930 *A = Y; 2931 Z = Y; 2932 2933 and the LOAD operation never appear outside of the CPU. 2934 2935 2936 AND THEN THERE'S THE ALPHA 2937 -------------------------- 2938 2939 The DEC Alpha CPU is one of the most relaxed CPUs there is. Not only that, 2940 some versions of the Alpha CPU have a split data cache, permitting them to have 2941 two semantically-related cache lines updated at separate times. This is where 2942 the data dependency barrier really becomes necessary as this synchronises both 2943 caches with the memory coherence system, thus making it seem like pointer 2944 changes vs new data occur in the right order. 2945 2946 The Alpha defines the Linux kernel's memory barrier model. 2947 2948 See the subsection on "Cache Coherency" above. 2949 2950 2951 ============ 2952 EXAMPLE USES 2953 ============ 2954 2955 CIRCULAR BUFFERS 2956 ---------------- 2957 2958 Memory barriers can be used to implement circular buffering without the need 2959 of a lock to serialise the producer with the consumer. See: 2960 2961 Documentation/circular-buffers.txt 2962 2963 for details. 2964 2965 2966 ========== 2967 REFERENCES 2968 ========== 2969 2970 Alpha AXP Architecture Reference Manual, Second Edition (Sites & Witek, 2971 Digital Press) 2972 Chapter 5.2: Physical Address Space Characteristics 2973 Chapter 5.4: Caches and Write Buffers 2974 Chapter 5.5: Data Sharing 2975 Chapter 5.6: Read/Write Ordering 2976 2977 AMD64 Architecture Programmer's Manual Volume 2: System Programming 2978 Chapter 7.1: Memory-Access Ordering 2979 Chapter 7.4: Buffering and Combining Memory Writes 2980 2981 IA-32 Intel Architecture Software Developer's Manual, Volume 3: 2982 System Programming Guide 2983 Chapter 7.1: Locked Atomic Operations 2984 Chapter 7.2: Memory Ordering 2985 Chapter 7.4: Serializing Instructions 2986 2987 The SPARC Architecture Manual, Version 9 2988 Chapter 8: Memory Models 2989 Appendix D: Formal Specification of the Memory Models 2990 Appendix J: Programming with the Memory Models 2991 2992 UltraSPARC Programmer Reference Manual 2993 Chapter 5: Memory Accesses and Cacheability 2994 Chapter 15: Sparc-V9 Memory Models 2995 2996 UltraSPARC III Cu User's Manual 2997 Chapter 9: Memory Models 2998 2999 UltraSPARC IIIi Processor User's Manual 3000 Chapter 8: Memory Models 3001 3002 UltraSPARC Architecture 2005 3003 Chapter 9: Memory 3004 Appendix D: Formal Specifications of the Memory Models 3005 3006 UltraSPARC T1 Supplement to the UltraSPARC Architecture 2005 3007 Chapter 8: Memory Models 3008 Appendix F: Caches and Cache Coherency 3009 3010 Solaris Internals, Core Kernel Architecture, p63-68: 3011 Chapter 3.3: Hardware Considerations for Locks and 3012 Synchronization 3013 3014 Unix Systems for Modern Architectures, Symmetric Multiprocessing and Caching 3015 for Kernel Programmers: 3016 Chapter 13: Other Memory Models 3017 3018 Intel Itanium Architecture Software Developer's Manual: Volume 1: 3019 Section 2.6: Speculation 3020 Section 4.4: Memory Access